Lab Report #3-2-4: 0.1 M NaC2H3O2 solution, using the given pH data, calculate value of (Ka or Kb) O 1.7 x 10-9 O 1.7 x 10-7 O 1.7 x 10-6 O 1.7 x 10-8
Lab Report #3-2-4: 0.1 M NaC2H3O2 solution, using the given pH data, calculate value of (Ka or Kb) O 1.7 x 10-9 O 1.7 x 10-7 O 1.7 x 10-6 O 1.7 x 10-8
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![## Lab Report #3-2-4:
### Calculation of \( K_a \) or \( K_b \) from pH Data
A 0.1 M solution of sodium acetate (NaC\(_2\)H\(_3\)O\(_2\)) is used in this exercise. Using the given pH data, determine the value of the acid dissociation constant (\( K_a \)) or the base dissociation constant (\( K_b \)):
- [ ] \( 1.7 \times 10^{-9} \)
- [ ] \( 1.7 \times 10^{-7} \)
- [ ] \( 1.7 \times 10^{-6} \)
- [ ] \( 1.7 \times 10^{-8} \)
Instructions:
1. Calculate the concentration of hydronium ions \([H_3O^+]\) using the pH data.
2. Use the relationship between the pH and \([H_3O^+]\) ions to determine whether you need \( K_a \) or \( K_b \).
3. Apply the respective formula to calculate the dissociation constant.
### Steps to Follow:
1. **Determine the pH of the solution.**
2. **Calculate the hydronium ion concentration, \([H_3O^+]\), using the formula:**
\[ [H_3O^+] = 10^{-\text{pH}} \]
3. **Use the appropriate formula for \( K_a \) or \( K_b \):**
For \( K_a \):
\[ K_a = \frac{[H_3O^+][A^-]}{[HA]} \]
For \( K_b \):
\[ K_b = \frac{[OH^-][B^+]}{[BOH]} \]
4. **Select the correct dissociation constant value based on your calculations.**
This exercise will help in understanding the dissociation of weak acids or bases and the relationship between pH, \( K_a \), and \( K_b \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a70e2d2-d641-435a-b212-d4266cff05fc%2F8e9e68b7-d73f-4a68-a8d6-f386dd63459f%2Fcpotch9_processed.png&w=3840&q=75)
Transcribed Image Text:## Lab Report #3-2-4:
### Calculation of \( K_a \) or \( K_b \) from pH Data
A 0.1 M solution of sodium acetate (NaC\(_2\)H\(_3\)O\(_2\)) is used in this exercise. Using the given pH data, determine the value of the acid dissociation constant (\( K_a \)) or the base dissociation constant (\( K_b \)):
- [ ] \( 1.7 \times 10^{-9} \)
- [ ] \( 1.7 \times 10^{-7} \)
- [ ] \( 1.7 \times 10^{-6} \)
- [ ] \( 1.7 \times 10^{-8} \)
Instructions:
1. Calculate the concentration of hydronium ions \([H_3O^+]\) using the pH data.
2. Use the relationship between the pH and \([H_3O^+]\) ions to determine whether you need \( K_a \) or \( K_b \).
3. Apply the respective formula to calculate the dissociation constant.
### Steps to Follow:
1. **Determine the pH of the solution.**
2. **Calculate the hydronium ion concentration, \([H_3O^+]\), using the formula:**
\[ [H_3O^+] = 10^{-\text{pH}} \]
3. **Use the appropriate formula for \( K_a \) or \( K_b \):**
For \( K_a \):
\[ K_a = \frac{[H_3O^+][A^-]}{[HA]} \]
For \( K_b \):
\[ K_b = \frac{[OH^-][B^+]}{[BOH]} \]
4. **Select the correct dissociation constant value based on your calculations.**
This exercise will help in understanding the dissociation of weak acids or bases and the relationship between pH, \( K_a \), and \( K_b \).

Transcribed Image Text:### Solutions and Their pH Values
Below is a table showing the pH values of various solutions:
| **Solutions** | **pH values** |
|---------------------|---------------|
| H₂O (unboiled) | 3.5 |
| H₂O (boiled) | 7.0 |
| NaCl | 7.0 |
| NaC₂H₃O₂ | 9.1 |
| NH₄Cl | 4.5 |
| NaHCO₃ | 9.5 |
| Na₃PO₄ | 11.9 |
| Na₂CO₃ | 11.0 |
#### Explanation:
- **H₂O (unboiled)**: The pH value is 3.5, indicating that unboiled water is slightly acidic.
- **H₂O (boiled)**: Boiled water has a neutral pH value of 7.0.
- **NaCl (Sodium Chloride)**: The solution of sodium chloride has a neutral pH value of 7.0.
- **NaC₂H₃O₂ (Sodium Acetate)**: This solution is basic with a pH value of 9.1.
- **NH₄Cl (Ammonium Chloride)**: The pH value of ammonium chloride solution is 4.5, indicating it is acidic.
- **NaHCO₃ (Sodium Bicarbonate)**: This solution is basic with a pH of 9.5.
- **Na₃PO₄ (Sodium Phosphate)**: The solution is highly basic with a pH of 11.9.
- **Na₂CO₃ (Sodium Carbonate)**: Sodium carbonate solution is also basic with a pH value of 11.0.
This table helps in understanding the acidity or basicity of common solutions, which is essential for various scientific and educational purposes.
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