Determine the pH at the point in the titrátion of 40.0 mL of 0.200 M HC4H,O2 with 0.100 M Sr(OH)2 after 10.0 mL of the strong base has been added. The value of Ka for HC4H,O2 is 1.5 x 10-s. く PREV 2 1 3 NEXT Based on the result of the acid-base reaction, set up the ICE table in order to determine the unknown. HC4H;O2(aq) H20(1) H3O*(aq) CAH,O2 (aq) Initial (M) Change (M) Equilibrium (M)
Determine the pH at the point in the titrátion of 40.0 mL of 0.200 M HC4H,O2 with 0.100 M Sr(OH)2 after 10.0 mL of the strong base has been added. The value of Ka for HC4H,O2 is 1.5 x 10-s. く PREV 2 1 3 NEXT Based on the result of the acid-base reaction, set up the ICE table in order to determine the unknown. HC4H;O2(aq) H20(1) H3O*(aq) CAH,O2 (aq) Initial (M) Change (M) Equilibrium (M)
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What is the definition of kb and the ph
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Question 13 of 18
Determine the pH at the point in the titration of 40.0 mL of 0.200 M HC4H,O2 with
0.100 M Sr(OH)2 after 10.0 mL of the strong base has been added. The value of
Ka for HC4H,O2 is 1.5 x 10-5.
PREV
2
3
4
NEXT
Based on the result of the acid-base reaction, set up the ICE table in order to determine the
unknown.
HC4H;O2(aq) +
H20(1)
1)
H;O*(aq)
C4H,O2 (aq)
+
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
0.100
0.120
0.140
0.0200
0.0400
+x
0.100 + x
0.100 - x
0.120 + x
0.120 - x
0.140 + x
0.140 - x
0.0200 + x
0.0200 - x
0.0400 + x
0.0400 - x
Transcribed Image Text:Question 13 of 18
Determine the pH at the point in the titration of 40.0 mL of 0.200 M HC4H,O2 with
0.100 M Sr(OH)2 after 10.0 mL of the strong base has been added. The value of
Ka for HC4H,O2 is 1.5 × 10¯,
1
3
4
NEXT
Use the table below to determine the moles of reactant and product after the reaction of the acid
and base. You can ignore the amount of liquid water in the reaction.
OH (aq)
H2O(I)
C4H;O2 (aq)
+
HC4H;O2(aq) +
Before (mol)
Change (mol)
After (mol)
5 RESET
0.100 + x
0.100 - x
0.100
0.200
+x
-X
2.00 x 103
-2.00 x 10"3
6.00 x 103
-6.00 x 103
0.200 + x
0.200 - x
1.00 × 103
-1.00 × 103
7.00 × 10
-7.00 × 10~3
8.00 x 10"3
-8.00 x 103
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