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13. Calculate the PH of a 0.1M HA solution. Ka for HA is 7.2 x 10-5 |4.0 ONone of the others 2.1 ]2.3 26

13. Calculate the PH of a 0.1M HA solution. Ka for HA is 7.2 x 10-5 |4.0 ONone of the others 2.1 ]2.3 26

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**13. Calculate the PH of a 0.1M HA solution. \( K_a \) for HA is \( 7.2 \times 10^{-5} \).** - **A** 2.1 - **B** 4.0 - **C** None of the others - **D** 2.3 --- **14. Give the positive root for the following quadratic formula:** \[ x^2 + 5.5 \times 10^{-11} \cdot x - 5.5 \times 10^{-12} = 0 \] - **A** None of the others - **B** 5.6 - **C** 4.6 - **D** 5.1 - **E** 4.1 --- **15. The PH of a 0.1M HF/0.1M NaF \((K_a\) for HF is \(7.2 \times 10^{-5}\)) buffer solution is:** - **A** None of the others - **B** 3.1 - **C** 6.1 - **D** 5.1 - **E** 4.1 --- **16. The expression of \( K_{sp} \) for \( \text{Ni(OH)}_2 \) is:** - **A** \([\text{Ni}^{2+}] \cdot [\text{OH}^-]^2\) - **B** \([\text{Ni}^{2+}]^2 \cdot [\text{OH}^-]^2\) - **C** None of the others - **D** \([\text{Ni}^+] \cdot [\text{OH}^-]\) --- **17. The solubility equilibrium for \( \text{Mn(IO}_3)_2 \) is:** - **A** None of the others - **B** \( \text{Mn(IO}_3)_2(s) \rightleftharpoons \text{Mn}^{2+}_{(aq)} + 2\text{IO}_3^-_{(aq)} \) - **C** \( \text{Mn(IO}_3)_2(s) \rightleftharpoons \text{Mn}_{(aq)}^{+}
Transcribed Image Text:**13. Calculate the PH of a 0.1M HA solution. \( K_a \) for HA is \( 7.2 \times 10^{-5} \).** - **A** 2.1 - **B** 4.0 - **C** None of the others - **D** 2.3 --- **14. Give the positive root for the following quadratic formula:** \[ x^2 + 5.5 \times 10^{-11} \cdot x - 5.5 \times 10^{-12} = 0 \] - **A** None of the others - **B** 5.6 - **C** 4.6 - **D** 5.1 - **E** 4.1 --- **15. The PH of a 0.1M HF/0.1M NaF \((K_a\) for HF is \(7.2 \times 10^{-5}\)) buffer solution is:** - **A** None of the others - **B** 3.1 - **C** 6.1 - **D** 5.1 - **E** 4.1 --- **16. The expression of \( K_{sp} \) for \( \text{Ni(OH)}_2 \) is:** - **A** \([\text{Ni}^{2+}] \cdot [\text{OH}^-]^2\) - **B** \([\text{Ni}^{2+}]^2 \cdot [\text{OH}^-]^2\) - **C** None of the others - **D** \([\text{Ni}^+] \cdot [\text{OH}^-]\) --- **17. The solubility equilibrium for \( \text{Mn(IO}_3)_2 \) is:** - **A** None of the others - **B** \( \text{Mn(IO}_3)_2(s) \rightleftharpoons \text{Mn}^{2+}_{(aq)} + 2\text{IO}_3^-_{(aq)} \) - **C** \( \text{Mn(IO}_3)_2(s) \rightleftharpoons \text{Mn}_{(aq)}^{+}
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