1. Fit a straight line to the following data points using excel program to obtain the concentration corresponding to absorbance=1.9. To calculate the concentration, you need to create a graph and get the trendline equation for the linear part of graph going through the intercept (0,0). Absorbanc e Conc (MM) 0.04 0.12 0.2 0.32 0.56 0.88 1.12 0.2 0.6 1.1 1.6 2 2.3 2.5 Absorbance 1.8 1.6 14 1.2 1 0.8 896 0.6 0.4 0.2 0 0 0.05 y=5.1263x 0.1 0.15 Concentration (mm) 0.2 y = (5.1236)(x) y = 1.9 1.9 = (5.1236)(x) x = 1.9/5.1236 x = 0.371 mM Concentration when the absorbance is 1.9 = 0.371 mM 0.25 0.3 0.35

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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1. Fit a straight line to the following data points using excel program to obtain the
concentration corresponding to absorbance-1.9. To calculate the concentration, you
need to create a graph and get the trendline equation for the linear part of graph going
through the intercept (0,0).
Absorbanc
e
Conc
(mm)
0.04
0.12
0.2
0.32
0.56
0.88
1.12
0.2
0.6
1.1
1.6
2
2.3
2.5
Absorbance
18
1.6
14
1.2
1
0.8
0.6
0.4
0.2
O
D
0.05
y=5.1263x
0.1
0.15
Concentration (mm)
0.2
y = (5.1236)(x)
y = 1.9
1.9 = (5.1236)(x)
x = 1.9/5.1236
x = 0.371 mM
Concentration when the absorbance is 1.9 = 0.371 mM
0.25
0.3
0.35
Transcribed Image Text:1. Fit a straight line to the following data points using excel program to obtain the concentration corresponding to absorbance-1.9. To calculate the concentration, you need to create a graph and get the trendline equation for the linear part of graph going through the intercept (0,0). Absorbanc e Conc (mm) 0.04 0.12 0.2 0.32 0.56 0.88 1.12 0.2 0.6 1.1 1.6 2 2.3 2.5 Absorbance 18 1.6 14 1.2 1 0.8 0.6 0.4 0.2 O D 0.05 y=5.1263x 0.1 0.15 Concentration (mm) 0.2 y = (5.1236)(x) y = 1.9 1.9 = (5.1236)(x) x = 1.9/5.1236 x = 0.371 mM Concentration when the absorbance is 1.9 = 0.371 mM 0.25 0.3 0.35
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