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Knight P6.67 A 70 kg cyclist is coasting down a long hill that has a 5° slope. His cross-section area is 0.35 m², his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is r = 0.02, and the density of air is 1.2 kg/m³. What speed does he eventually reach? 5⁰ y FN W Farag Ffriction X

Knight P6.67 A 70 kg cyclist is coasting down a long hill that has a 5° slope. His cross-section area is 0.35 m², his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is r = 0.02, and the density of air is 1.2 kg/m³. What speed does he eventually reach? 5⁰ y FN W Farag Ffriction X

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3. Knight P6.67 A 70 kg cyclist is coasting down a long hill that has a 5° slope. His cross-section area is 0.35 m², his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is r = 0.02, and the density of air is 1.2 kg/m³. What speed does he eventually reach? 5⁰ y FN W Farag Ffriction X
Transcribed Image Text:3. Knight P6.67 A 70 kg cyclist is coasting down a long hill that has a 5° slope. His cross-section area is 0.35 m², his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is r = 0.02, and the density of air is 1.2 kg/m³. What speed does he eventually reach? 5⁰ y FN W Farag Ffriction X
Useful information Newton's 2nd law component form ΣΕ = max X ΣFy = may Static, kinetic, and rolling friction Quadratic drag F, < μgFN Fk = μk FN Fr=r FN F₁ = CpAv²
Transcribed Image Text:Useful information Newton's 2nd law component form ΣΕ = max X ΣFy = may Static, kinetic, and rolling friction Quadratic drag F, < μgFN Fk = μk FN Fr=r FN F₁ = CpAv²
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