Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Can you help me break down the fragmentation of this mass spec spectra? Although the compound is not given, using the H NMR, C NMR and IR spectras that were also given, I found the compound to be CH3-COOH-CH2-CH2-CH2-CH3 (butyl acetate) In this Mass spec, it is given that M+=116 and I have found that fragmenting CH3 is 101, then CH2 is 87, and CH2 again is 73. I am just lost on where to go from there, while being left with CH3-COOH-CH2, because there are multiple peaks between 43 and 73 that I can't seem to figure out. Any help would be great!

Can you help me break down the fragmentation of this mass spec spectra? Although the compound is not given, using the H NMR, C NMR and IR spectras that were also given, I found the compound to be CH3-COOH-CH2-CH2-CH2-CH3 (butyl acetate) In this Mass spec, it is given that M+=116 and I have found that fragmenting CH3 is 101, then CH2 is 87, and CH2 again is 73. I am just lost on where to go from there, while being left with CH3-COOH-CH2, because there are multiple peaks between 43 and 73 that I can't seem to figure out. Any help would be great!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question

Can you help me break down the fragmentation of this mass spec spectra? Although the compound is not given, using the H NMR, C NMR and IR spectras that were also given, I found the compound to be CH3-COOH-CH2-CH2-CH2-CH3 (butyl acetate)

In this Mass spec, it is given that M+=116 and I have found that fragmenting CH3 is 101, then CH2 is 87, and CH2 again is 73. I am just lost on where to go from there, while being left with CH3-COOH-CH2, because there are multiple peaks between 43 and 73 that I can't seem to figure out.

Any help would be great! 

Relative Intensity 100 80 Ö O 20 миниито 10 M+= 116 20 30 40 50 60 m/z 70 powqurubluqunuqtangguptag 100 110 120 80 90
Transcribed Image Text:Relative Intensity 100 80 Ö O 20 миниито 10 M+= 116 20 30 40 50 60 m/z 70 powqurubluqunuqtangguptag 100 110 120 80 90
H H—C-C Η Η Η Η Η -C-C-C-C-H Η Η Η Η Butyl Acetate
Transcribed Image Text:H H—C-C Η Η Η Η Η -C-C-C-C-H Η Η Η Η Butyl Acetate
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Mass Spectrometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS