Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
100%
I really need help analyzing and interpreting these spectra to find a chemical formula and compound structure!

Transcribed Image Text:210
200
190
84
-17094
170
160
150
140
130
120
110
100
f1 (ppm)
90
-77.16 CDCB
-64.05
13C NMR in CDCl3 (solvent is labeled)
-30.34
30
69 02-
2881
20
10
-10
-4500000
--4000000
-3500000
-3000000
-2500000
-2000000
-1500000
-1000000
-500000

Transcribed Image Text:10.0
2.5
4.0
9.0
3.5
8.5
T
3.0
8.0
7.26 CDC13
25
11 (ppm)
7.5
7.0
2.0
SS
6.5
15
B
10
5.5
-4.0x10²
--3.0x10²
-2.0x10²
10x10
00
5.0
11 (ppm)
4.5
4.07
---4.05
007
4.0
2.03
3.5
291
29 T
1.60
3.0
AST
AST
1.58
1.57
KT.
25
1.57
1.55
1.54
1.40
F000-2
20
-1.38
at
86 19
Forz
102
TTT T
15
1.36
F-2009
1.38
0.94
0.5
260
¹H NMR in CDC13 (solvent is labeled). Multiplicity for signals 1.25-1.75 is multiplet.
0.89
4.5×10²
40x10
-35x10
-3.0x10²
--25×10²
-20x10
15x10²
10x10
--50x10⁰
Loo
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Follow-up Questions
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Follow-up Question
hello, thanks so much for this!! i also have an IR and Mass Spec spectra with this assignment. I figured out the IR to match these same signals and come up with this same compound, but I cant seem to figure out how to do the fragmentation on the Mass Spec. It is given then M+ = 116, but there's baRely a peak there

Transcribed Image Text:Relative Intensity
100
80
Ö
O
20
миниито
10
M+= 116
20
30 40
50
60
m/z
70
powqurubluquruqtangengungstag
100 110 120
80
90
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