estion 3A flat belt drive connects two pulleys 5 meters apart. The 2m pulley diameterdriver rotates at 350rpm, and the driven pulley has a diameter of 1.5m. Thethickness and the mass of the belt drive is 5mm and 0.6kg respectively. Thecoefficient of friction between the belt and the pulley is 0.25. The beltexperience 3% of slip during power transmission with a maximum tension of1200N.Calculate the speed and torque of the driven shaft.

Given, Distance between the two pulleys, L=5mDriver diameter, D1=2mN1=350rpmDriven diameter,…

Answered: Jestion 3 A flat belt drive connects…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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16. (Force and Motion - II) Two blocks of masses m, are suspended by a cord from a pulley which is attached to in front of a wall as shown in figure. A horizontal force of 8.3 N is applied to second block and the coefficients of static and kinetic frictions between the wall and the second block are 0.4 and 0.2. Cord and pulley are massless and pulley is frictionless. 1 kg and m2 = 2 kg %3D If the blocks, which are initially at rest, start moving when they are released; i Draw the free body diagrams for both blocks. m1 m) ii Find the acceleration of the blocks. Answer: ii) a = 4.49 m/s
A brake test is carried out with a balance and a direct current motor. The purpose of this experiment is to calculate the torque on the motor shaft. The following values were obtained in the experiment. U=220 volts., I=107 amps, n = 1200 rpm. The length from the axis of the motor shaft to the point where the brake lever presses on the scale is L=80 cm. and the weight read on the balance G = 20 Kg. is Accordingly, calculate the following values: a) the shaft power taken from the shaft of the motor, b) the electrical power drawn by the motor from the mains c) motor total losses and motor efficiency Calculate
Hello, please solve this problem and explain a little bit, Thank you very much
Q1/ An open belt drive connected two pulleys 120 cm and 50 cm diameter on parallel shafts 4 m apart. The belt weights 0.9 kg/m length and maximum tension in it is not to exceed 2000 N. 0.3. The 120 cm pulley, which is the driver, runs at 200 rpm. Due to belt slip on one of the pulleys, the velocity of the driven shaft is only 450 rpm. Calculate the torque on each of the two shafts and power transmitted.
A 2:1 speed reduction drive (Fig Q4) between two parallel shafts at 1200 mm centre distance is being provided by a V-belt of mass 0.5 kg/m. The diameter of the driving pulley is 200 mm and the driving shaft rotates at 900 rev/min. The driven pulley is 400 mm diameter. The angle of the pulley grooves is 40°, and the coefficient of friction between belt and pulleys is 0.35. If the maximum beit tension is 400 N determine: (i) The linear belt speed and the centripetal tension due to that belt speed. (ii) The angle of lap on each pulley (iii) The maximum power that may be transmitted Ø200 1200 Ø400
The tensions in the tight and slack side of a belt drive system are 1850 N and 525 respectively. If the belt speed is 8 m/s what power in kW will be transmitted with no slippage
I need the answer as soon as possible
Q2/ A conical clutch an included angle of 60°. the outer radius and inner diameters are 80 and 20 cm respectively. Calculate the maximum and minimum intensity of pressure and force required to press the two halves together if it is to transmit 20 MW, at 60 rev/h. the coefficient of friction is 0.3, Use both the uniform wear theory and the uniform pressure theory.
A belt pulley is designed as a flywheel. it has a moment of inertia of 100kgm^2 and is supposed to be accelerated from a resting position to a rotational frequency of 600 min^-1 within 15 seconds. you have to calculate the acceleration torque without considering the friction of the bearing

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