J. J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer, a device that measures the ratio of mass m to (positive) charge g of an ion. The spectrometer consists of two regions as shown in the figure. (Figure 1) In the first region an electric field accelerates the ion and in the second the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured and then the m/q ratio can be Figure V E 1 of 1 Part A After being accelerated to a speed of 1.21x105 m/s, the particle enters a uniform magnetic field of strength 0.700 T and travels in a circle of radius 35.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. View Available Hint(s) IVE ΑΣΦ x" x E √x √x X m/q= 4.94-105 Submit Previous Answers a O P Pearson X IXI X Incorrect; Try Again: 5 attempts remaining ? X-10" X kg/C
J. J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer, a device that measures the ratio of mass m to (positive) charge g of an ion. The spectrometer consists of two regions as shown in the figure. (Figure 1) In the first region an electric field accelerates the ion and in the second the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured and then the m/q ratio can be Figure V E 1 of 1 Part A After being accelerated to a speed of 1.21x105 m/s, the particle enters a uniform magnetic field of strength 0.700 T and travels in a circle of radius 35.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. View Available Hint(s) IVE ΑΣΦ x" x E √x √x X m/q= 4.94-105 Submit Previous Answers a O P Pearson X IXI X Incorrect; Try Again: 5 attempts remaining ? X-10" X kg/C
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Text Transcription for Educational Website**
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**J.J. Thomson and the Mass Spectrometer**
J.J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer, a device that measures the ratio of mass \( m \) to (positive) charge \( q \) of an ion.
The spectrometer consists of two regions as shown in the figure. In the first region, an electric field accelerates the ion, and in the second, the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured, and then the \( m/q \) ratio can be found.
**Experiment Details**
- After being accelerated to a speed of \( 1.21 \times 10^5 \, \text{m/s} \), the particle enters a uniform magnetic field of strength \( 0.700 \, \text{T} \) and travels in a circle of radius \( 35.0 \, \text{cm} \).
- The results of this experiment allow one to find \( m/q \).
**Question**
Find the ratio \( m/q \) for this particle.
Express your answer numerically in kilograms per coulomb.
- \( m/q = \)
Input: \( 4.94 \times 10^5 \, \text{kg/C} \)
Error: Incorrect; Try Again. 5 attempts remaining.
**Figure Explanation**
The figure illustrates the process within the mass spectrometer:
- An ion with mass \( m \) is accelerated by an electric field \( \vec{E} \) across a potential difference \( V \).
- It then enters a region with a magnetic field \( \vec{B_0} \) and follows a curved path with radius \( R \).
---
**Note:** The diagram includes arrows indicating the direction of the electric field \( \vec{E} \) and magnetic field \( \vec{B_0} \). The ion's trajectory is shown as a circular arc, and the measurement of its radius \( R \) is critical for determining the mass-to-charge ratio.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2bfb154-6516-44b8-a74c-6088eccd0097%2F0eb75f2b-9d30-4c1f-9e31-051feb98cf87%2Frq848dm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Text Transcription for Educational Website**
---
**J.J. Thomson and the Mass Spectrometer**
J.J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer, a device that measures the ratio of mass \( m \) to (positive) charge \( q \) of an ion.
The spectrometer consists of two regions as shown in the figure. In the first region, an electric field accelerates the ion, and in the second, the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured, and then the \( m/q \) ratio can be found.
**Experiment Details**
- After being accelerated to a speed of \( 1.21 \times 10^5 \, \text{m/s} \), the particle enters a uniform magnetic field of strength \( 0.700 \, \text{T} \) and travels in a circle of radius \( 35.0 \, \text{cm} \).
- The results of this experiment allow one to find \( m/q \).
**Question**
Find the ratio \( m/q \) for this particle.
Express your answer numerically in kilograms per coulomb.
- \( m/q = \)
Input: \( 4.94 \times 10^5 \, \text{kg/C} \)
Error: Incorrect; Try Again. 5 attempts remaining.
**Figure Explanation**
The figure illustrates the process within the mass spectrometer:
- An ion with mass \( m \) is accelerated by an electric field \( \vec{E} \) across a potential difference \( V \).
- It then enters a region with a magnetic field \( \vec{B_0} \) and follows a curved path with radius \( R \).
---
**Note:** The diagram includes arrows indicating the direction of the electric field \( \vec{E} \) and magnetic field \( \vec{B_0} \). The ion's trajectory is shown as a circular arc, and the measurement of its radius \( R \) is critical for determining the mass-to-charge ratio.
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