### J.J. Thomson and the Mass SpectrometerJ.J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer. This device measures the ratio of mass \( m \) to (positive) charge \( q \) of an ion.The spectrometer consists of two regions as shown in the figure (Figure 1). In the first region, an electric field accelerates the ion, and in the second, the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured, and then the \( m/q \) ratio can be determined.#### Figure Explanation:- The diagram shows two regions separated by a barrier.- On the left, an electric field \( E \) accelerates the ion, indicated by parallel lines with arrows.- On the right, the ion moves in a circular path due to a magnetic field \( B \), indicated by dots representing a field coming out of the page.- The radius of the circular arc is marked \( R \).### Calculation ExampleAfter being accelerated to a speed of \( 1.21 \times 10^5 \, \text{m/s} \), the particle enters a uniform magnetic field of strength \( 0.700 \, \text{T} \) and travels in a circle of radius \( 35.0 \, \text{cm} \) (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find \( m/q \).**Find the ratio \( m/q \) for this particle.** Express your answer numerically in kilograms per coulomb.\[ \frac{m}{q} = \](Answer field for \( m/q \) in kg/C)*Submit your answer, and feedback is provided.*

Required : q/m for the particle.

After being accelerated to a speed of 1.21x105 m/s, the particle enters a uniform magnetic field of strength 0.700 T and travels in a circle of radius 35.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. View Available Hint(s)

After being accelerated to a speed of 1.21x105 m/s, the particle enters a uniform magnetic field of strength 0.700 T and travels in a circle of radius 35.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. View Available Hint(s)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

### J.J. Thomson and the Mass Spectrometer

J.J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer. This device measures the ratio of mass \( m \) to (positive) charge \( q \) of an ion.

The spectrometer consists of two regions as shown in the figure (Figure 1). In the first region, an electric field accelerates the ion, and in the second, the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured, and then the \( m/q \) ratio can be determined.

#### Figure Explanation:

- The diagram shows two regions separated by a barrier.
- On the left, an electric field \( E \) accelerates the ion, indicated by parallel lines with arrows.
- On the right, the ion moves in a circular path due to a magnetic field \( B \), indicated by dots representing a field coming out of the page.
- The radius of the circular arc is marked \( R \).

### Calculation Example

After being accelerated to a speed of \( 1.21 \times 10^5 \, \text{m/s} \), the particle enters a uniform magnetic field of strength \( 0.700 \, \text{T} \) and travels in a circle of radius \( 35.0 \, \text{cm} \) (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find \( m/q \).

**Find the ratio \( m/q \) for this particle.**
Express your answer numerically in kilograms per coulomb.

\[ \frac{m}{q} = \]

(Answer field for \( m/q \) in kg/C)

*Submit your answer, and feedback is provided.*

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