Thomson is best known for his discoveries about the re of cathode rays. His other important contribution the invention, together with one of his students, of nass spectrometer, a device that measures the ratio ass m to (positive) charge q of an ion. spectrometer consists of two regions as shown in gure.(Figure 1) In the first region an electric field lerates the ion and in the second the ion follows a lar arc in a magnetic field. The radius of curvature of rc can be measured and then the m/q ratio can be d. Part A After being accelerated to a speed of 1.00×105 m/s, the particle enters a uniform magnetic field of strength 0.900 T and travels in a circle of radius 33.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. ► View Available Hint(s) 17 ΑΣΦ m/q= Submit Previous Answers ? kg/C

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
**J. J. Thomson and the Mass Spectrometer**

J. J. Thomson is best known for his discoveries concerning cathode rays. Another significant contribution he made, with the help of one of his students, was the invention of the mass spectrometer. This device measures the ratio of mass \( m \) to (positive) charge \( q \) of an ion.

The spectrometer is composed of two regions, as illustrated in Figure 1. In the first region, an electric field accelerates the ion. In the second region, the ion moves in a circular arc within a magnetic field. By measuring the radius of curvature of this arc, we can determine the \( \frac{m}{q} \) ratio.

---

**Part A: Calculating the \( \frac{m}{q} \) Ratio**

When accelerated to a speed of \( 1.00 \times 10^5 \, \text{m/s} \), the particle enters a uniform magnetic field with a strength of 0.900 T. It then travels in a circle with a radius of 33.0 cm, a measurement obtained by observing where it strikes the screen, as depicted in the figure.

This experiment allows us to calculate the \( \frac{m}{q} \) ratio for the particle.

**Task:** Determine the \( \frac{m}{q} \) ratio for this particle.

Express your answer numerically in kilograms per coulomb.

[Input Box: \( \frac{m}{q} = \, \) _______ kg/C]

[Submit Button] [Previous Answers Link]

**Hints Available for Assistance**
Transcribed Image Text:**J. J. Thomson and the Mass Spectrometer** J. J. Thomson is best known for his discoveries concerning cathode rays. Another significant contribution he made, with the help of one of his students, was the invention of the mass spectrometer. This device measures the ratio of mass \( m \) to (positive) charge \( q \) of an ion. The spectrometer is composed of two regions, as illustrated in Figure 1. In the first region, an electric field accelerates the ion. In the second region, the ion moves in a circular arc within a magnetic field. By measuring the radius of curvature of this arc, we can determine the \( \frac{m}{q} \) ratio. --- **Part A: Calculating the \( \frac{m}{q} \) Ratio** When accelerated to a speed of \( 1.00 \times 10^5 \, \text{m/s} \), the particle enters a uniform magnetic field with a strength of 0.900 T. It then travels in a circle with a radius of 33.0 cm, a measurement obtained by observing where it strikes the screen, as depicted in the figure. This experiment allows us to calculate the \( \frac{m}{q} \) ratio for the particle. **Task:** Determine the \( \frac{m}{q} \) ratio for this particle. Express your answer numerically in kilograms per coulomb. [Input Box: \( \frac{m}{q} = \, \) _______ kg/C] [Submit Button] [Previous Answers Link] **Hints Available for Assistance**
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Rutherford's scattering experiment
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON