**Problem 2:**Using conservation of energy, **show** that the speed $ v $ of an electron leaving your "electron gun" can be written in terms of the electron accelerating potential $ V $, electron charge $ e $, and electron mass $ m_e $ as:\[v = \sqrt{\frac{2eV}{m_e}}\]*(Equation 5)* **Text Transcription:**be perpendicular to the electron velocity, causing the electrons to move in a circular path. By varying the current going through the Helmholtz coils you will be able to vary the applied magnetic field and thus change the radius of the electron paths. The magnetic field will be produced using "Helmholtz coils" that produce a magnetic field strength (at the center of the coil configuration) given by:\[B = \frac{8}{5\sqrt{5}} \frac{\mu_0 IN}{R},\]where $ R $ is the radius of the coils, $ N $ is the number of turns per coil ($ N = 124 $ in your set-up), $\mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{A/m}$, and $ I $ is the current flowing through the coils.---**Graph/Diagram Explanation:***Figure 2:*(a) *Schematic Diagram of the Vacuum Tube:*- This diagram illustrates the setup used to determine the value of $ e/m_e $, which is the charge-to-mass ratio of the electron.- The setup includes a helium-filled vacuum tube.- The electron gun emits electrons that follow a circular path, depicted in blue, due to the influence of magnetic fields produced by Helmholtz coils.- Key components highlighted include the helium-filled vacuum tube, electron gun, electron's path, and deflection plates.(b) *Cathode and Anode Arrangement of the Electron Gun:*- This schematic details the arrangement of the electron gun components.- It consists of a cathode (marked with a negative sign), an anode (marked with a positive sign), a grid, and a heater.- The electron movement direction within this setup is indicated by a blue arrow moving towards the anode.- The diagram also highlights the location of deflection plates used to influence electron direction.

Solution Given dataUsing conservation of energy show that the speed v of an electron leaving…

Answered: 2. Using conservation of energy, show…

Similar questions

Particle Electron Proton Neutron Relative Charge -1 +1 0 What is: Electric Charge (C) -1.60 x 10-19 +1.60 x 10-19 0 a) The mass defect? Relative Mass (u) 5.485779 x 10-4 1.007276 1.008665 1u = 1.6605 x 10-27 kg 1eV = 1.60 x 10-19 Joules The 'cheating' equivalence shortcut 1u- 931.5 MeV He is the most abundant isotope of helium. Its mass is 6.6447x 10-27kg. Mass (kg) b) The binding energy of the nucleus in joules? 9.109390 x 10-31 1.672623 x 10-27 1.674929 x 10-27
4. MILLIKAN EXPERIMENT. An oil drop with a mass of 3.1 x10-1$kg absorbs 11 electrons, and then falls through an opening in two parallel, horizontal plates 1.8 cm apart. The upper plate is positive. a) Determine the charge absorbed by the oil drop. b) Determine the required potential difference between the plates in order for the oil drop to be suspended between the two plates.
Electron + Proton Calculate the potential energy of an electron and proton in a hydrogen atom (use 1 eV = 1.6× 10-¹⁹ J): In Joules: In eV: eV Use that the magnitude charge on an electron and a proton is 1.6×10-1⁹C, the atomic radius is 5.3×10 11m, and k=9 × 10⁹ Nm²/c².
17) How many eV's are created when a frequency of 8.77 e 15 is made from a collapsed electron_ f I be-19
Q9. Determine the distance between two protons at which the Coulomb potential equals the Coulomb barrier of 200 keV.
If the intensity of a light source is increased while the frequency and the metal surface remain the same, which of the following will occur? a. Electrons will be emitted at an increased rate with more average energy per electron. b. Electrons will be emitted at the same rate with the same average energy per electron. c. Electrons will be emitted at the same rate but with less average energy per electron. d. Electrons will be emitted at the same rate but with more average energy per electron. e. Electrons will be emitted at an increased rate with the same average energy per electron.
Which should I choose and why
25. Alpha particles are emitted in nuclear decay processes with typical energies of 5 MeV. In analogy with Example 4.9, determine the range of kinetic energies of an alpha particle trapped in a nucleus-sized region and deduce whether the alpha particle can exist inside the nucleus.
A 83.0 kg athlete running a "4-minute mile" (i.e. 4.00 min/mile) _____ nm an electron (me = 9.10939 1028 g) moving at 3.90 106 m/s in an electron microscope _____ nm.

2. Using conservation of energy, show that the speed v of an electron leaving your "electron gun" can be written in terms of the electron accelerating potential V, electron charge e and electron mass me as: v= 2eV me (5)