2. Suppose you can find the velocity of an object with a 'photogate'. Thephotogate measure the time the object is breaking a beam of light. So ifthe object is .12 meters long and the time blocking the beam is 135 ms thevelocity will be:.12metersmv =.89(1).135secondsSuppose two photogates are set up on a 'frictionless' incline plane (0 :18°). Assume the time through gate 1 is 232 ms and the second gate is0.7 meters down the plane. What will be the time through the second gate.(The mass sliding has a length of .15 meters)Cafz La=9,8sin G

Answered: 2. Suppose you can find the velocity of…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

2. Suppose you can find the velocity of an object with a 'photogate'. The
photogate measure the time the object is breaking a beam of light. So if
the object is .12 meters long and the time blocking the beam is 135 ms the
velocity will be:
.12meters
m
v =
.89
(1)
.135seconds
Suppose two photogates are set up on a 'frictionless' incline plane (0 :
18°). Assume the time through gate 1 is 232 ms and the second gate is
0.7 meters down the plane. What will be the time through the second gate.
(The mass sliding has a length of .15 meters)
Cafz L
a=9,8sin G

Expert Solution

Step 1

$G i v e n : A n g l e, θ = 18 ° G a t e l e n g h t, L = 0.7 m S l i d i n g l e n g h t, l = 0.15 m T i m e, t = 232 m s = 0.232 s F i n d t h e t i m e t h r o u g h t h e s e c o n d g a t e .$

$N o w, V_{1} = \frac{l}{t} = \frac{0.15 m}{0.232 s} = 0.646 m / s W e k n o w n a l o n g t h e i n c l i n e a c c e l e r a t i o n i s (g \sin θ), u \sin g e q u a t i o n . V_{2}^{2} - v_{1}^{2} = (2 g \sin θ) l V_{2} = \sqrt{v_{1}^{2} + (2 g \sin θ) l} = \sqrt{{(0.646 m / s)}^{2} + (2 \times 9.81 m / s^{2} \times \sin 18 ° \times 0.7 m)} = 2.159 m / s$

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