It is suspected that25% of children may have an adverse reaction to the new RTS,S/AS01 (RTS,S) vaccine thatwas recommended in October this year by the World Health Organization for the preventionof P. falciparum malaria in children living in the sub-Saharan Africa, where transmission ismoderate to high. Suppose the Health Science Faculty of UP is going to test the vaccine on60 patients.Let: X = the number of children who experienced an adverse reaction.Xsample proportion of children who experienced adverse reaction.60The distribution of X iswith an expected value ofand a standard deviation ofRound your answer to 4 decimal places. .b)The sampling distribution of p is: (Choose all the correct choices, marks will be subtractedfor incorrect choices.)approximately normalskewed to the leftbinarydiscretebinomialskewed to the rightsymmetriccontinuousnormalc)Give the expected value and standard deviation of p.• Expected value, µp =Round your answer to 2 decimal places.• Standard deviation, on =Round your answer to 4 decimal places. d)The probability that more than 21% of the children will experience an adverse reaction isRound your answer to 4 decimal places.e)It is known that twenty percent of the sample proportions are less thanRound your answer to 4 decimal places.f)The sample proportion, p, will be within a distance offrom the populationproportion, ninety percent of the time.Round your answer to 4 decimal places.

As per our guidelines, we are allowed to answer first three sub-parts only .Thanks Given: Proportion…

Answered: It is suspected that 25% of children…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose we want to assess the effect of a one-day SAT prep class at a 5% level of significance. Scores on the SAT writing exam can range from 200 to 800. A random sample of 50 students takes the SAT writing test before and after a prep class. We test the hypotheses: H0 : μ = 0 Ha : μ > 0 where µ is the mean of the difference in SAT writing scores (after minus before) for all students who take the SAT prep class. The sample mean is 5 with a standard deviation of 18. Since the sample size is large, we are able to conduct the T-Test. The T-test statistic is approximately 1.96 with a P-value of approximately 0.028. Explain ?
Cloud seeding, a process in which chemicals such as silver iodide and frozen carbon dioxide are introduced by aircraft into clouds to promote rainfall was widely used in the 20-th century. Recent research has questioned its effectiveness [Journal of Atmospheric Research (2010, Vol. 97 (2), pp. 513-525)]. An experiment was performed by randomly assigning 52 clouds to be seeded or not. The amount of rain generated was then measured in acre-feet. Here are the data for the unseeded and seeded clouds: Unseeded: 81.2 26.1 95.0 41.1 28.6 21.7 11.5 68.5 345.5 321.2 1202.6 1.0 4.9 163.0 372.4 244.3 47.3 87.0 26.3 24.4 830.1 4.9 36.6 147.8 17.3 29.0 Seeded: 274.7 302.8 242.5 255.0 17.5 115.3 31.4 703.4 334.1 430.0 1697.8 118.3 198.6 129.6 274.7 119.0 1656.0 7.7 40.6 92.4 200.7 32.7 4.1 978.0 489.1 2745.6 Construct a frequence distribution for the combined cloud-seeding rain measurements. Use 6 bins. Class Frequency -250 < x < 250 250 < x < 750 750 < x < 1250 1250 < x < 1750 1750 < x < 2250 2250…
use a cutoff value of 5%.
Given a random sample of size n from a uniform population with a = 0, find an estimator for ß by the method of moments.
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 116, x = 12.5, and s = 6.35. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)State the appropriate null and alternative hypotheses. H0: ? = 15Ha: ? ≠ 15H0: ? = 15Ha: ? > 15 H0: ? = 15Ha: ? ≤ 15H0: ? = 15Ha: ? < 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject…
The human resources director of a large company recently asked her staff to conduct a study of the airline miles traveled by executives of the company during the most recent calendar year. The analyst assigned to the project randomly sampled 25 male executives and 25 female executives. Of particular interest to the HR director is whether males have greater variability in miles flown than females. The statistics available below were computed from the samples. Based on these data, what should the HR director conclude if an alpha level equal to 0.01 is used? LOADING... Click the icon to view the statistics about the number of miles flown. Males Females Mean Miles 73,262 66,888 St. Deviation Miles 2,568 1,539 Sample Size 25 25 Let sample 1 be males and sample 2 be females. What are the null and alternative hypotheses? A. H0: σ21=σ22 HA: σ21≠σ22 B. H0: σ21≤σ22 HA: σ21>σ22 C. H0: σ21≥σ22 HA:…
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Show all work/steps! You must use JMP to analyze data.
Suppose that one chemical plant in a large corporation is accused of exceeding the established limits of toxins being released into the atmosphere. A decision is made to test whether or not the mean level of toxins exceeds the tolerance level μ0=100μ0=100 ppm (parts per million). How would the null and alternative hypotheses be set up given that the researcher is working for the corporation? How would those hypotheses change if the researcher is working for the Environmental Protection Agency (EPA)?

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