When only two treatments are involved, ANOVA and the Student’s t-test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course as a distance course format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups.   Traditional Lecture Distance 33 46 38 35 40 44 32 30 31 41 36 31   41   46      Click here for the Excel Data File.   a-1. Complete the ANOVA table. (Round your SS, MS, and F values to 2 decimal places and p-value, F crit to 4 decimal places.)   a-2. Use a α = 0.05 level of significance, compute the critical value. (Round your answer to 2 decimal places.)   b. Using the t-test from Chapter 11, compute t. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)   c. There is any difference in the mean test scores.

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When only two treatments are involved, ANOVA and the Student’s t-test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course as a distance course format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups.
 

Traditional Lecture Distance
33 46
38 35
40 44
32 30
31 41
36 31
  41
  46
 

 
 Click here for the Excel Data File.
 

a-1. Complete the ANOVA table. (Round your SS, MS, and F values to 2 decimal places and p-value, F crit to 4 decimal places.)

 



a-2. Use a α = 0.05 level of significance, compute the critical value. (Round your answer to 2 decimal places.)

 



b. Using the t-test from Chapter 11, compute t(Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)

 



c. There is any difference in the mean test scores.

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