Is the reaction endothetmic or exothermic？Fe3+(aq) + HSCN (aq) ↔ FeSCN2+(aq) + H+ (aq) PLES44Data sheetTable 1CRLSUNJCH)CResyCNSampl Volume ofVolume of Volume ofInitial%T[HSCN]Initial0.200 MFe(NOs)Absorbance at 445R.KSCN(Fe]0.250 M0.00040MHNOnm10.00 ml0. 250(D ano CO.2512H)10.00 ml0.00 ml0.olM20.0bo-00soz000-0s 0.00001 O 250 +0. iu10.00 ml8.00 ml2.00 ml0-OIM 0.00016M 13.9o 8569952310.00 ml6.00 ml4.00 mlD.3500124140. O1M 0.0012M 3.3 |0 6326R.Efe] LHSCN] I fesCN] l IH' ]410.00 ml4.00 ml6.00 ml0. Olm 0.000 SM 37.1 |0.4Au0. 250Table 2kaya l. 259Sample Volume of Volume of Volume of0.0200 M KSCNFe(NO)3Initial0. 250095904Initial%TAbsorbanc0.250 M0,00040M HNO,[Fe][HSCN]e at 445E Fets] [HSCN1 [FesON t2] [H'1nm110.00 ml10,00 ml0.00 ml0-0lM 0 23.0.63640.01000.00a0-350key = 0.87ーズE 0-oloo-0.0006H 0-0002-0.00 o-0000067386|0.35o +D.000673860. a0999332.10,00 ml8.00 ml2.00 ml-J0.OIM 0.000IEM 31.9 0.4962310,00 ml6.00 ml4.00 ml0.00O|2 M44. I O. 355644.10. 35560.000067 3860.25000673860.0IM410,00 ml4.00 ml6.00 mlTHI Fe'3] IHSCNI0-01000.OIM 0.000YM 55.8O. 25 345/(0.000046770.2o10.00 ml4,00 ml6.00 mlIfe SaN 21warm0.000g.0. 250Kay= 0-3505.2- lg(231): 0.63642-ly (s: 0. 49622.0.30499533.0-000153310.0000 467 297.25000 46732- ty (44.1):0.35562-し55.3): 0.25らs4Averge Ka1.65 658 + 1.299 +u.s7+0.55030=1.08402 3tFo+14[fa SCNITH]e sca1AbsCFesaN]+ H* cag.Fe cag + HSCN,a4s Fe ScNO.1000.250C.0.250 +3KSNA HNO 3 ClassS HSCN t KNO34.00X 10* M0-250My=4947.6x +0222.R230.9911.

The reaction is: Fe3+(aq) + HSCN (aq) ↔ FeSCN2+(aq) + H+ (aq)

Answered: Is the reaction endothetmic or…

Science

Chemistry

Is the reaction endothetmic or exothermic？Fe3+(aq) + HSCN (aq) ↔ FeSCN2+(aq) + H+ (aq)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter28: Atomic Spectroscopy

Section: Chapter Questions

Problem 28.15QAP

See similar textbooks

Related questions

Q: A reaction is initiated by preparing an aqueous solution with 0.421 M silver ion, Ag+ (aq), and…

A: • So, The correct answer is : Kc = 6.02E1Explanation:Step 1:

Q: Ag+ (aq) + NH3(aq) Ag(NH3)*(aq) Ag(NH3)* (aq) + NH3(aq) → Ag(NH3)2* (aq) Equal volumes of 0.1…

A: The objective of the question is to determine which silver species, Ag+ or Ag(NH3)2+, will have the…

Q: References] Obtain the equilibrium constant for the reaction HCN(aq) = H+ (aq) + CN¯(aq) From the…

Q: Part C Classify reaction as exothermic or endothermic. Dehydratation hydroxide: Ba(OH),…

A: Exothermic reactions are those reactions in which heat is released during the reaction. The value of…

Q: Four different solutions were prepared at the same concentration: HCl(aq), HF(aq), NaOH(aq), and…

A: pH is defined as negative logarithm of hydrogen ions concentration.

Q: What is the equilibrium expression (Keq) for the reaction below? Mg3(PO4)2(s) 3 Mg2+(aq) + 2…

A: The given equilibrium reaction is as follows: Mg3PO42(s) ⇌ 3Mg2+(aq) + 2PO43-(aq) The…

Q: Mg(OH)2(s) Mg2+(aq) + 2OH- (aq) Write the balanced net ionic equation for the equilbrium

A: Balanced net equation for equilibrium given as

Q: 8. (a) HA(aq) is a weak acid with a dissociation constant, Ka, of 8.8 x 10−12. What is the pH of a…

Q: For the reaction below, Kc = 1.10 × 10⁻⁸. Note Kc is sometimes called K. What is the equilibrium…

Q: If the value of K, for HCN is 4.9 x 10-10 at 25 °C, calculate the equilibrium constant for: CN (aq)…

Q: A weak acid, HA, has pKa=6.2. If a solution of NaA (aq) is prepared, what does the pH of the…

A: The Henderson–Hasselbalch equation relates the pH of a solution containing a mixture of the two…

Q: The acid ionization constant for Pb(H2O)62+(aq) is 6.3×107. Calculate the pH of a 0.0651 M solution…

Q: For the reaction below, Kc = 1.10 × 10⁻⁸. Note Kc is sometimes called K. What is the equilibrium…

Q: 6. Calculate the average from the 2 experiments for each time point. Plot your data on a graph and…

A: The speed at which a reactant is converted to products is called the rate of a reaction. The study…

Q: For the reaction of hydrazine (N2H4) in water, H,NNH, (ag) + H20(1) = H,NNH3* (aq) + OH (ag) K, is…

Q: Consider the following equilibrium: Ag+(aq) + 2 NH3 (aq) ⇌ Ag(NH3)2+ The equilibrium…

Q: Macmillan Learning If the K, of a monoprotic weak acid is 3.3 x 10-6, what is the pH of a 0.41 M…

Question

Is the reaction endothetmic or exothermic？Fe3+(aq) + HSCN (aq) ↔ FeSCN2+(aq) + H+ (aq)

PLES
44
Data sheet
Table 1
CRLSUNJCH)
CResyCN
Sampl Volume of
Volume of Volume of
Initial
%T
[HSCN]
Initial
0.200 M
Fe(NOs)
Absorbanc
e at 445
R.
KSCN
(Fe]
0.250 M
0.00040M
HNO
nm
10.00 ml
0. 250
(D ano CO.2512H)
10.00 ml
0.00 ml
0.olM
2
0.0bo-00soz000-0s 0.00001 O 250 +0. iu
10.00 ml
8.00 ml
2.00 ml
0-OIM 0.00016M 13.9
o 8569952
3
10.00 ml
6.00 ml
4.00 ml
D.350012414
0. O1M 0.0012M 3.3 |0 6326
R.
Efe] LHSCN] I fesCN] l IH' ]
4
10.00 ml
4.00 ml
6.00 ml
0. Olm 0.000 SM 37.1 |0.4Au
0. 250
Table 2
kaya l. 259
Sample Volume of Volume of Volume of
0.0200 M KSCN
Fe(NO)3
Initial
0. 250095904
Initial
%T
Absorbanc
0.250 M
0,00040M HNO,
[Fe]
[HSCN]
e at 445
E Fets] [HSCN1 [FesON t2] [H'1
nm
1
10.00 ml
10,00 ml
0.00 ml
0-0lM 0 23.
0.6364
0.0100
0.00a
0-350
key = 0.87
ーズ
E 0-oloo-0.0006H 0-0002-0.00 o-0000067386|0.35o +D.00067386
0. a099933
2.
10,00 ml
8.00 ml
2.00 ml
-J
0.OIM 0.000IEM 31.9 0.4962
3
10,00 ml
6.00 ml
4.00 ml
0.00O|2 M44. I O. 3556
44.10. 3556
0.000067 386
0.2500067386
0.0IM
4
10,00 ml
4.00 ml
6.00 ml
TH
I Fe'3] IHSCNI
0-0100
0.OIM 0.000YM 55.8
O. 25 34
5/
(0.000046770.2o
10.00 ml
4,00 ml
6.00 ml
Ife SaN 21
warm
0.000g.
0. 250
Kay= 0-3505.
2- lg(231): 0.6364
2-ly (s: 0. 4962
2.
0.30499533.
0-000153310.0000 467 297
.25000 4673
2- ty (44.1):0.3556
2-し55.3): 0.25らs4
Averge Ka
1.65 658 + 1.299 +u.s7+0.55030
=1.08402

3t
Fo
+14
[fa SCNITH]
e sca1
Abs
CFesaN]
+ H* cag.
Fe cag + HSCN,a4s Fe ScN
O.100
0.250
C.
0.250 +3
KSNA HNO 3 ClassS HSCN t KNO3
4.00X 10* M
0-250M
y=4947.6x +0222.
R230.9911.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

In the concentration range of 1 to 100 g/mL P, phosphate suppresses the atomic absorption of Ca in a linear manner. The absorbancc levels off, however, between 100 and 300 g/mL P. Explain. How can this effect be reduced?
The max of aspirin (molar mass 180g/mol) in neutral solution is 225 nm and & is 650 mol-¹Lcm ¹. An absorbance of 1.80 was measured for a solution of aspirin, with a 1 cm path length. Calculate the concentration of the aspirin solution.
An unknown sample of Yellow 6 solution has the absorbance equal to 0.96. The slope of the Beer's law calibration plot constructed using a 3.8E-5M stock solution of Yellow 6 is 0.0117 (%) 1. What is the molar concentration of the unknown sample (in mole L-¹)? Please give your answer to 3 significant figures (1 additional SF is used to minimize rounding errors). M Hint
Unrounded Rounded ε∗,L/μmol 0.0259825 0.0260 Heres the data if needed: TZ # Concentration Absorbance at 430 nmnm 1 33.6480 0.931 2 25.2360 0.757 3 16.8420 0.210 4 8.41200 0.137 5 4.20600 0.122
At 580 nm, which is the wavelength of its maximum absorption, the complex Fe(SCN)2+ has a molar absorptivity of 7.00 I03L cm-1 mol-1.Calculate (a) the absorbance of a 4.47 10-5 M solution of the complex at 580 nm in a 1.00-cm cell. (b) the absorbance of a solution in a 2.50-cm cell in which the concentration of the complex is one half that in(a). (c) the percent transmittance of the solutions described in (a) and (b). (d) the absorbance of a solution that has half the transmittance of that described in (a).
The acid-base indicator HIn undergoes the following reaction in dilute aqueous solution: HIncolor1H++Incolor2 The following absorbance data were obtained for a 5.00 I0-4 M solution of HIn in 0.1 M NaOH and 0.1 M HC1. Measurements were made at wavelengths of 485 nm and 625 nm with 1.00-cm cells. 0.1 M NaOH A485 = 0.075 A625 = 0.904 0.1 M HC1 A485 = 0.487 A625 = 0.181 In the NaOH solution, essentially all of the indicator is present as In-; in the acidic solution, it is essentially all in the form of HIn. (a) Calculate molar absorptivities for In- and HIn at 485 and 625 nm. (b) Calculate the acid dissociation constant for the indicator ¡fa pH 5.00 buffer containing a small amount of the indicator exhibits an absorbance of 0.567 at 485 nm and 0.395 at 625 nm (1.00-cm cells). (c) What is the pH of a solution containing a small amount of the indicator that exhibits an absorbance of0.492 at 485 nm and 0.245 at 635 nm (1.00-cm cells)? (d) A 25.00-mL aliquot of a solution of purified weak organic acid HX required exactly 24.20 mL of a standard solution of a strong base to reach a phenolphthalein end point. When exactly 12.10 mL of the base was added to a second 25.00-mL aliquot of the acid, which contained a small amount of the Indicator under consideration, the absorbance was found to be 0.333 at 485 nm and 0.655 at 625 nm (1.00-cmcells). Calculate the pH of the solution and Ka for the weak acid. (e) What would be the absorbance of a solution at 485 and 625 nm (1.50-cm cells) that was 2.00 10-4 M in the indicator and was buffered to a pH of 6.000?
The chromium in an aqueous sample was determined by pipetting 10.0 ml. of the unknown into each of five 50.0-mL volumetric flasks. Various volumes of a standard containing 12.2 ppm Cr were added to the flasks, following which the solutions were diluted to volume. Unknown,mLStandard, mLAbsorbancc 10.00.00.201 10.010.0 0.292 10.020.0 0.378 10.030.0 0.467 10.040.0 0.554 (a) Plot the data using a spreadsheet. (b) Determine an equation for the relationship between absorbance and volume of standard. (c) Calculate the statistics for the least-squares relationship in (b). (d) I)ctcrmine the conccnt ration oÍCr in ppm in the sample. (e) Find the standard deviation of the result in (d).
Given the Information that Fe3++Y4FeYKi=1.01025Cu2++Y4CuY2Ki=6.31018 and the further information that, among the several reactants and products, only CuY2- absorbs radiationat 750 nm, describe how Cu(II) could be used as an indicator for the photometric titration of Fe(III) with H2Y2-. Reaction:+ Fe3++ H2Y2- FeY- + 2H+.
Do you have any clues??
THANSHITTANCETST Relative Intensity LOD 5D Unknown #2 Elemental Analysis: 55.81% Carbon, 7.03% Hydrogen, 37.17% Oxygen Exchanges 100 MS-NW-4945 80- 60 40 40 20 0 10 20 30 40 40 4000 Mass Spec Mass of Molecular lon= 86 m/z 550 50 60 70 80 - 90 100 110 120 m/z IR 3000 2000 AVENUMBER 1500 1000 500 1H NMR with D₂O 5.32 ppm 5.25 ppm 6.07 ppm Chemical Formula: Proposed Structure: 12 15 13C NMR 6 PPM 200 180 160 140 120 100 CDS-03-015 ppm HDI Calculation: 88 80 60 60 40 40 2.90 ppm 20 20 0
d=2r Asignment sphere is te cur pressue Caertod on it is OKIOS Nm-2 Cmormal ofrtmos pherie pressure)- The sphere is lovseped into the Ocaen To a depth A. initially surrounderd by airsand at ohich the prissure s 2.0x 10t Nm-², The wolume ot The gphere in air is osm3. By haw much does Drd its wolime chenge once it
12/ACCORDINg to the Bihe matel 4.When'elcotaon jumps from n-4 to n-2 IS the eneryy dBsOPBeD oR emitter Bi WoUlt an ektron jump Arom n=4 to n-1 invelve 7. the in dunf