Integrate your expression for M(x) twice to obtain expressions for slope and deflection respectively. Each integration wll introduce a constant. Use boundary conditions to solve for these constants and for the reaction moment MA. MAis positive it it acts in the direction shown. MA MB B Ay Answer: kN-m2 C1 = kN-m3 C2 = Attempts: 0 of 1 used Subm kN-m MA the part above.
Integrate your expression for M(x) twice to obtain expressions for slope and deflection respectively. Each integration wll introduce a constant. Use boundary conditions to solve for these constants and for the reaction moment MA. MAis positive it it acts in the direction shown. MA MB B Ay Answer: kN-m2 C1 = kN-m3 C2 = Attempts: 0 of 1 used Subm kN-m MA the part above.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:1used
Integrate your expression for M(x) twice to obtain expressions for slope and deflection respectively. Each integration will
introduce a constant. Use boundary conditions to solve for these constants and for the reaction moment MA. Ma is positive if it
acts in the direction shown.
MA
MB
B
L.
Ay
Answer:
kN-m2
C1 -
kN-m3
C2
Attempts: 0 of 1 used Submit A
kN-m
i
MA
the part above

Transcribed Image Text:A beam is loaded and supported as shown.
(a) Use the double-integration method to determine the reactions at supports A and B.
(b) Draw the shear-force and bending-moment diagrams for the beam.
(c) Determine the deflection in the middle of the span.
Assume w = 11 kN, L = 7.4 m and El - 6.9 x 104 kN-m2 is constant for the beam.
V.
L.
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