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int i; for (i = 0; i < 5; i++) { vec.push_back(i*2); } vector::iterator v = ++vec.begin(); while( ++v != vec.end()) { cout << ((*v/8)? *v:*v/8); } system("pause"); return 0; } Answer:

int i; for (i = 0; i < 5; i++) { vec.push_back(i*2); } vector::iterator v = ++vec.begin(); while( ++v != vec.end()) { cout << ((*v/8)? *v:*v/8); } system("pause"); return 0; } Answer:

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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What is the output of the following code after fixing the e Jint main() { vector<int> vec; int i; for (i = 0; i < 5; i++) { vec.push_back(i*2); } vector<int>::iterator v = ++vec.begin(); while( ++v != vec.end()) { cout << ((*v/8)? *v:*v/8); } system("pause"); return 0; Answer:
Transcribed Image Text:What is the output of the following code after fixing the e Jint main() { vector<int> vec; int i; for (i = 0; i < 5; i++) { vec.push_back(i*2); } vector<int>::iterator v = ++vec.begin(); while( ++v != vec.end()) { cout << ((*v/8)? *v:*v/8); } system("pause"); return 0; Answer:
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