or> a(numRows); // vector of vector to store character in each rows   int i = 0; // variable to determine in which row we must add particular character   bool direction = true; // variable to determine the direction of movement   for (char ch : s)   {   a[i].push_back(ch);   if (direction == true) // if direction is down => increment i   i++;   if (i == numRo

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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string convert(string s, int numRows)
  {
  vector<vector<char>> a(numRows); // vector of vector to store character in each rows
  int i = 0; // variable to determine in which row we must add particular character
  bool direction = true; // variable to determine the direction of movement
  for (char ch : s)
  {
  a[i].push_back(ch);
  if (direction == true) // if direction is down => increment i
  i++;
  if (i == numRows) // if i reached end => reverse the direction and decrement i
  {
  direction = false;
  i--;
  }
  if (direction == false) // if direction is up => decrement i
  i--;
  if (i <= 0) // if i reached start => reverse the direction and set i to 0
  {
  direction = true;
  i = 0;
  }
  }
   
  string str = ""; // forming the final string to return
  for (vector<char> c : a)
  {
  for (char ch : c)
  str += ch;
  }
  return str;
  }
   
  int main() // driver function
  {
  string str = "PAYPALISHIRING";
  string ans = convert(str,3);
  cout << ans;
 

return0;.

 

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