Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements inthe vector. Otherwise, output the even elements in the vector. End each number with a newline.Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is:-91Note: (x % 2 != 0) returns true if x is odd.int value;int i;bool isodd;7891011121314151617181920212223 }cin >> value;while (value != 0) {}for (i = 0; i < vect1.size(); ++i) {if (vect1[i] % 2 != 0 )cout << "\n" << vect1[i];}vect1.push_back(value);cin >> value;Checkreturn 0;1Next level2X 1: Compare output34For input -9 12 -6 1 0, the vector elements are -9, 12, -6, and 1. The last element, 1, is odd. The odd elements in the vector, -9and 1, are output, each on a new line.Not all tests passed.2V3

The problem with your code is your given condition is - If the value of vector is odd then print.…

Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements. the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2 != 0) returns true if x is odd. int value; int i; bool isodd; 7 8 9 10 11 12 13 14 15 6789RN 16 17 18 19 20 21 22 23 } cin >> value; while (value != 0) { } for (i = 0; i < vect1.size(); ++i) { if (vectl[i] % 2 != 0) cout << "\n" << vect1[i]; } vect1.push_back(value); cin >> value; Check return 0; 1 Next level 2 3

Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements. the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2 != 0) returns true if x is odd. int value; int i; bool isodd; 7 8 9 10 11 12 13 14 15 6789RN 16 17 18 19 20 21 22 23 } cin >> value; while (value != 0) { } for (i = 0; i < vect1.size(); ++i) { if (vectl[i] % 2 != 0) cout << "\n" << vect1[i]; } vect1.push_back(value); cin >> value; Check return 0; 1 Next level 2 3

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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