Inside a square conductive material, a static magnetic field is present H(x,y,z)-0 ax- 2z ay + y az (A/m). We are looking to evaluate the current circulating inside the conductive material. The amperian loop is shown in the figure below. The current I(A) using the left or the right side of stokes theorem equals: A(0,1,3) D(0,3,3) Amperian loop B(0,1,1) C(0,3,1) Conductive material N +
Inside a square conductive material, a static magnetic field is present H(x,y,z)-0 ax- 2z ay + y az (A/m). We are looking to evaluate the current circulating inside the conductive material. The amperian loop is shown in the figure below. The current I(A) using the left or the right side of stokes theorem equals: A(0,1,3) D(0,3,3) Amperian loop B(0,1,1) C(0,3,1) Conductive material N +
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![Inside a square conductive material, a static magnetic field is present H(x,y,z)%3D0 ax-2z ay+
y az (A/m). We are looking to evaluate the current circulating inside the conductive
material. The amperian loop is shown in the figure below. The current I(A) using the left or
the right side of stokes theorem equals:
A(0,1,3)
D(0,3,3)
Amperian loop
B(0,1,1)
C(0,3,1)
Conductive material
N +](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45ec0afe-b7c9-45c8-bd67-2221f08741f3%2F060d916f-34c4-43d3-843f-b289aead3ce6%2Ftw44me_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Inside a square conductive material, a static magnetic field is present H(x,y,z)%3D0 ax-2z ay+
y az (A/m). We are looking to evaluate the current circulating inside the conductive
material. The amperian loop is shown in the figure below. The current I(A) using the left or
the right side of stokes theorem equals:
A(0,1,3)
D(0,3,3)
Amperian loop
B(0,1,1)
C(0,3,1)
Conductive material
N +
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