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How the Biot-Savart Law Differs from Ampère's Law A current Io flows up the z-axis from z = z, to
z = 22 as shown below.
%3D
Z2
(a) Use the Biot-Savart law to show that the magnetic field in the z = 0 plane is
Ho lo
{cos 02 – cos 01}6.
4π ρ
B(p, 6, 0) =
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Review I Cor A 103 A current circulates around a 2.00-mm-diameter superconducting ring. What is the ring's magnetic dipole moment? Express your answer in amper-meters squared with the appropriate units. View Available Hint(s) ? A· m? Submit Part B What is the on-axis magnetic field strength 5.40 cm from the ring? Express your answer with the appropriate units. • View Available Hint(s) HA ? B = Value Units Submit
hand written plzzz
y Figure 3: 7= xi+ yj+zk = pcos cos oi + p sin oj + zk = pp+ zk and i = dr dt -p sin oi + p cos oj + k = po + zk . Notice that cyclotron angular velocity we = do COS is a negative constant, i.e. in the figure the particle is circulating clockwise. 3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = it + üz = ü + ij at position relative to origin experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] : d mv2 m[v² + v?] du - 0 = dt (a) : qü x B m ä - i [gữ x B] = ū. [m- = constant (True, False) dt 2 (b) : A [B x Č) Č [Ä x B] = B IC x A] (True, False)
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