3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = vt + 7z = 7 + T at position f relative to origin experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] : du d mv? m[v로 + 매 dữ (a) : qü x B - 7. (gữ x B] = ở . (m-1 - 0 = (True, False) m a constant dt dt 2 (b) : Ä [B x Č) Č. [Ä x B] = B [Č × A] (True, False)

icon
Related questions
Question
y
Figure 3: 7= xi+ yj+zk = pcos
cos oi + p sin oj + zk = pp+ zk and i =
dr
dt
-p sin oi + p cos oj + k = po + zk . Notice that cyclotron angular velocity we =
do
COS
is a negative constant, i.e. in the figure the particle is circulating clockwise.
3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = it + üz = ü + ij at position relative to origin
experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] :
d mv2
m[v² + v?]
du
- 0 =
dt
(a) : qü x B
m ä - i [gữ x B] = ū. [m-
= constant
(True, False)
dt 2
(b) : A [B x Č)
Č [Ä x B] = B IC x A] (True, False)
Transcribed Image Text:y Figure 3: 7= xi+ yj+zk = pcos cos oi + p sin oj + zk = pp+ zk and i = dr dt -p sin oi + p cos oj + k = po + zk . Notice that cyclotron angular velocity we = do COS is a negative constant, i.e. in the figure the particle is circulating clockwise. 3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = it + üz = ü + ij at position relative to origin experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] : d mv2 m[v² + v?] du - 0 = dt (a) : qü x B m ä - i [gữ x B] = ū. [m- = constant (True, False) dt 2 (b) : A [B x Č) Č [Ä x B] = B IC x A] (True, False)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer