3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = vt + 7z = 7 + T at position f relative to origin experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] : du d mv? m[v로 + 매 dữ (a) : qü x B - 7. (gữ x B] = ở . (m-1 - 0 = (True, False) m a constant dt dt 2 (b) : Ä [B x Č) Č. [Ä x B] = B [Č × A] (True, False)
3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = vt + 7z = 7 + T at position f relative to origin experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] : du d mv? m[v로 + 매 dữ (a) : qü x B - 7. (gữ x B] = ở . (m-1 - 0 = (True, False) m a constant dt dt 2 (b) : Ä [B x Č) Č. [Ä x B] = B [Č × A] (True, False)
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Question
![y
Figure 3: 7= xi+ yj+zk = pcos
cos oi + p sin oj + zk = pp+ zk and i =
dr
dt
-p sin oi + p cos oj + k = po + zk . Notice that cyclotron angular velocity we =
do
COS
is a negative constant, i.e. in the figure the particle is circulating clockwise.
3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = it + üz = ü + ij at position relative to origin
experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] :
d mv2
m[v² + v?]
du
- 0 =
dt
(a) : qü x B
m ä - i [gữ x B] = ū. [m-
= constant
(True, False)
dt 2
(b) : A [B x Č)
Č [Ä x B] = B IC x A] (True, False)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90ba196a-a4da-4c5b-97fd-f3d58be17337%2Ff30436f5-41d1-417f-bc86-a47171e0198f%2Fbmf6byh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:y
Figure 3: 7= xi+ yj+zk = pcos
cos oi + p sin oj + zk = pp+ zk and i =
dr
dt
-p sin oi + p cos oj + k = po + zk . Notice that cyclotron angular velocity we =
do
COS
is a negative constant, i.e. in the figure the particle is circulating clockwise.
3. Consider a charged particle, q, in the presence of a magnetic field B with velocity i = it + üz = ü + ij at position relative to origin
experiencing a magnetic force qü x B. From the second law it follows that the kinetic energy of the particle remains constant[ see figure 3] :
d mv2
m[v² + v?]
du
- 0 =
dt
(a) : qü x B
m ä - i [gữ x B] = ū. [m-
= constant
(True, False)
dt 2
(b) : A [B x Č)
Č [Ä x B] = B IC x A] (True, False)
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