Initially, 4.0 moles of H₂(g) and 2.0 moles of N₂(g) were added to a 1.0-liter container and the following reaction then occurred: 3H₂(g) + N₂(g) = 2NH3(g) The equilibrium concentration of NH3(g) = 0.62 moles/liter at 700°C. What is the value of Ke at 700°C for the formation of ammonia? 1.2x 10-1 7.9 x 10-3 1.12 none of these 3.8 x 10-2

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Question 12
Initially, 4.0 moles of H₂(g) and 2.0 moles of N₂(g) were added to a 1.0-liter container
and the following reaction then occurred: 3H₂(g) + N₂(g) = 2NH3(g)
The equilibrium concentration of NH3(g) = 0.62 moles/liter at 700°C. What is the
value of Ke at 700°C for the formation of ammonia?
1.2x 10-1
7.9 x 10-3
1.12
none of these
3.8 x 10-²
Transcribed Image Text:Question 12 Initially, 4.0 moles of H₂(g) and 2.0 moles of N₂(g) were added to a 1.0-liter container and the following reaction then occurred: 3H₂(g) + N₂(g) = 2NH3(g) The equilibrium concentration of NH3(g) = 0.62 moles/liter at 700°C. What is the value of Ke at 700°C for the formation of ammonia? 1.2x 10-1 7.9 x 10-3 1.12 none of these 3.8 x 10-²
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