The equilibrium constant, K., for the following reaction is 55.6 at 698 K. H₂(g) +12(g) 2 HI(g) Calculate the equilibrium concentrations of reactants and product when 0.299 moles of H₂ and 0.299 moles of 12 are introduced into a 1.00 L vessel at 698 K [H₂] = [1₂] = [HI] = M M M

The equilibrium constant, K., for the following reaction is 55.6 at 698 K. H₂(g) +12(g) 2 HI(g) Calculate the equilibrium concentrations of reactants and product when 0.299 moles of H₂ and 0.299 moles of 12 are introduced into a 1.00 L vessel at 698 K [H₂] = [1₂] = [HI] = M M M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: The equilibrium constant, Ke, for the following reaction is 55.6 at 698 K. H₂(g) + 12 (9) 2HI(g)…

Q: The equilibrium constant, K, for the following reaction is 1.29×10-² at 600 K. CoCl₂(g) →CO(g) +…

A: It is given that number of moles of COCl2=0.378 molesvolume of the…

Q: You have a reaction: C2H6(g) + C2(g) =C¿H5CI(s) + HCI(g). Determine the equilibrium concentrations…

A: Equilibrium: The stage in any chemical reaction where the concentration of the reactants and the…

Q: The equilibrium constant, Kc, for the following reaction is 1.29×10 at 600 K. COCI₂(g) =CO(g) +…

A: Information of question

Q: The equilibrium constant, Kc, for the following reaction is 0.0180 at 698 K. 2HI(g) → H₂(g) + 1₂ (9)…

Q: Phosphorus pentachloride decomposes according to the chemical equation…

A: Phosphorus pentachloride decomposes into phosphorus trichloride and chlorine gas. The equation for…

Q: Consider the following reaction where K, 34.5 at 1150 K 250) O 250g) A reaction mixture was found to…

A: if Qc = Kc ; reaction is at equilibrium , no net reaction Qc > Kc. Backward(reverse) reaction…

Q: The equilibrium constant, Ke, for the following reaction is 1.29×10-² at 600K. COCI,(g) co(g) +…

A: Given reaction is : COCl2 (g) <------------> CO (g) + Cl2 (g) Value of equilibrium constant =…

Q: A mixture of 0.452 M H,O, 0.448 M Cl,0, and 0.737 M HCIO are enclosed in a vessel at 25 °C. H,O(g) +…

Q: The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH,Cl½(g) CH,(g) + CC,(g)…

Q: The equilibrium constant, K., for the following reaction is 55.6 at 698 K. H2 (g) + I2 (g) =2 HI (g)…

A: For the given problem we are given the value of Kc = 55.6 for the forward reaction The reaction can…

Q: Consider this reaction which at a specified temperature has K =0.00183. 2 HI(g) H2(g) + I2(g) If…

Q: Consider the following reaction where K. = 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) A reaction…

Q: A student ran the following reaction in the laboratory at 663 K: 2 NH₂(g) → N₂(g) + 3 H₂(g) When she…

A: Answer:For any reaction, value of equilibrium constant is equal to the ratio of molar concentrations…

Q: The equilibrium constant, Ke, for the following reaction is 0.00650 at 298 K. 2NOBr(g) 2NO(g) + Br₂…

Q: 1.The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H2(g) + I2(g) 2HI(g)…

A: Kc = 55.6H2(g) + I2(g) 2HI(g)0.342 moles of H2 0.342 moles of I2 Volume = 1.00 LTemperature = 698…

Q: The equilibrium constant, Kc, for the following reaction is 1.29x10-2 at 600 K. CoCl₂(g) =CO(g) +…

Q: The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: 22HI(9) Calculate the…

Q: The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K. H₂ (9) + I2 (9) — 2HI(g)…

Q: Use the References to access important values if needed for this question. The equilibrium constant,…

Q: The equilibrium constant, Ke, for the following reaction is 0.0180 at 698 K. 2HI(g) → H₂(g) + 1₂ (9)…

A: Given, 2HI(g) ⇌ H2(g) + I2(g) Equilibrium constant (KC) = 0.0180 Temperature = 698 K Initially…

Q: Nzp+ 3Hug) NH3(g)+ energy Imagine a cylinder containing nitrogen gas (N2), hydrogen gas (H2), and…

A: The equilibrium reaction given is, => N2 (g) + 3 H2 (g) ------> 2 NH3 (g) + Energy. Given :…

Q: The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCI3(g) + Cl2(g)=PCI5(g)…

Q: A mixture of 0.452 M H,O, 0.448 M CI,0, and 0.737 M HCIO are enclosed in a vessel at 25 °C. H,O(g) +…

A: The question is based on the concept of chemical equilibrium. we have to calculate equilibrium…

Q: A mixture initially contains 0.0730 M carbon monoxide and 0.1713 M hydrogen gas at 800 K and allowed…

A: Given equilibrium is CO(g) + 3H2(g) ⇌ CH4(g) + H2O(g) Initial concentration of CO(g) = 0.0730 M…

Q: Consider the equilibrium system described by the chemical reaction below. The decomposition of NOBr…

Q: Calculating K from equilibrium concentrations and vice versa 8. At 298 K, the equilibrium constant…

A: Answer:For a given chemical reaction, value of equilibrium constant is always equal to the ratio…

Q: The equilibrium constant, Kc, for the following reaction is 5.54 at 350 K. 2XY(g) X2(g) + Y2(g)…

Q: For the reaction system: H2(g) + X2(g) = 2HX(g), Kc = 24.4 at 300 K. A system at equilibrium made up…

Q: Consider the reaction, which takes place at a certain elevated temperature CO(g) + NH3(g) =…

A: Given,

Q: The equilibrium constant, Kc, for the following reaction is 0.0180 at 698 K. 2HI(g) → H₂(g) + 12 (9)…

A: Given, 2HI (g) <---> H2 (g) + I2 (g) Equilibrium constant (Kc) = 0.0180 Initially moles of HI…

Q: Consider the following reaction where K. = 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) A reaction…

Q: What is the equilibrium constant for the following reaction, if a mixture at equilibrium contains…

A: The given balanced equation is:- CH4(g) + H2O(g) ⇔ CO(g) + 3H2(g) The given concentrations are :-…

Q: Write the expression for the equilibrium constant K, for the following reaction. Enclose pressures…

A: The equlibrium constant Kp is the ratio of partial pressure of product (along with its co- efficient…

Q: Use the References to access important values if needed for this question. The equilibrium constant,…

Q: Write the expression for the equilibrium constant K, for the following reaction. Enclose pressures…

A: Equilibrium constant Equilibrium expression can be formulated as amounts of products divide by…

Q: At a certain temperature, the equilibrium constant, ?, for the given reaction is 53.3.…

A: Given data is The equilibrium constant for the reaction H2(g) + I2(g) <====> 2HI(g) is 53.3…

Q: The equilibrium constant, K., for the following reaction is 1.29×10-2 at 600 K. COCI,(g)CO(g) +…

A: We have given that The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K.…

Q: The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H₂(g) + 1₂(g) →2HI(g)…

A: The equilibrium reaction is .The equilibrium constant is KC = 55.6 at 698 K.The initial number of…

Q: The equilibrium constant, K., for the following reaction is 77.5 at 600 K. Co(g) + C(g)=COC,(g)…

A: Kc = 77.5 Temperature 600 K Moles of CO = .231 Moles of Cl2 = .231 Volume of vessel = 1 L

Q: The equilibrium constant, Ko, for the following reaction is 55.6 at 698 K. Н2 (9) + I, (g) — 2 HІ…

A: In ICE table. I is initial concentration, C is change in concentration and E is equilibrium…

Q: The equilibrium constant, K, for the following reaction is 1.29x10-2 at 600 K. ? CoCl₂(g) CO(g) +…

A: The objective is to determine the equilibrium concentration of the reactant and…

Q: The equilibrium constant, Ke, for the following reaction is 1.20x102 at 500 K. PCI,(9) PC (9) +…

Q: Consider the following reaction where K. = 6.30 at 723 K: 2 NH3 (g): ÷N2 (g) + 3 H2 (g) A reaction…

A: Calculate Qc and then decide from the following informationIf Kc > Qc then to reach equilibrium,…

Q: The equilibrium constant, K, for the following reaction is 1.29x102 at 600 K. CoCl₂(g) co(g) +…

A: The given equilibrium reaction is COCl2(g) CO(g) + Cl2(g)The equilibrium constant of the…

Q: At a certain termperature, Kc = 0.914 for the reaction NO₂(g) + NO(g) = N₂O(g) + O₂(g) A mixture was…

A: Given :- NO2(g) + NO(g) ⇌ N2O(g) + O2(g) Number of moles of NO2 is 0.200 mol. Number of moles of…

Question

100%

The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K.
H₂(g) +12(g)
2 HI(g)
Calculate the equilibrium concentrations of reactants and product when 0.299 moles of H₂ and 0.299 moles of 12 are introduced into a 1.00 L vessel at 698 K.
[H₂] =
[1₂] =
[HI] =
M
M
M

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Defining equilibrium constant

VIEW

Step 2: Formation of ICE table

VIEW

Step 3: Calculation for unknown y

VIEW

Step 4: Calculation for equilibrium concentration of all the gases

VIEW

Solution

VIEW

Step by step

Solved in 5 steps with 12 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

The reaction N2(g) + 3 H2(g) ⇀↽ 2 NH3(g), has an equilibrium constant of 4.0 × 108 at 25◦C. What will eventually happen if 44.0 moles of NH3, 0.452 moles of N2, and 0.108 moles of H2 are put in a 10.0 liter container at 25◦C? More N2 and H2 will be formed. Nothing; the system is at equilibrium. More NH3 will be formed.
The equilibrium constant, K., for the following reaction is 1.29×102 at 600 K. CoC,(g) CO(g) + Cl(g) Calculate the equilibrium concentrations of reactant and products when 0.270 moles of COCI,(g) are introduced into a 1.00 L vessel at 600 K. [COC1] = M %3D [CO] M [Cl2] M
for this question. The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K. H₂(g) + I2(g) → 2HI(g) Calculate the equilibrium concentrations of reactants and product when 0.316 moles of H₂ and 0.316 moles of I2 are introduced into a 1.00 L vessel at 698 K. [H₂] [1₂] = = [HI] = M M M Submit Answer 8 more group attempts remaining Retry Entire Group
please explain and give complete answer
Write the expression for the equilibrium constant K, for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH, as (P NH3)². If either the numerator or denominator is 1, please enter 1 2 Nb2O5(s) + 4 NbO2(s) + 02(g) K =
A mixture of ammonia, nitrogen and hydrogen was allowed to come to equilibrium at 900 K. 2NH3 = 3H2 + N2 Ke = 0.0076 An analysis of the mixture at equilibrium revealed 0.31 M of H2 and 1.8 M of NH3. Determine the equilibrium concentration of N2 (in M) in this mixture. (with 2 significant figures)
The equilibrium constant, K., for the following reaction is 77.5 at 600 K. Co(g) + C,(g)=COC»(g) Calculate the equilibrium concentrations of reactant and products when 0.593 moles of CO and 0.593 moles of Cl, are introduced into a 1.00 L vessel at 600 K. [CO] M [Cl,] M [COCI,] =
At a certain termperature, Kc = 0.914 for the reaction NO₂(g) + NO(g) = N₂O(g) + O₂(g) A mixture was prepared containing 0.200 mol NO2, 0.300 mol NO, 0.150 mol N₂O, and 0.250 mol O₂ in a 8.00 L container. What will be the equilibrium concentrations of each gas? [NO₂] [NO] [N₂O] [0₂] i i i i M M M M
The equilibrium constant, Kc, for the following reaction is 0.0180 at 698 K. 2HI(g) → H₂(g) + 12 (9) Calculate the equilibrium concentrations of reactant and products when 0.305 moles of HI(g) are introduced into a 1.00 L vessel at 698 K. HI [H₂] [1₂] = = = M 3 M
The equilibrium concentrate of H2: 0.048 M The equilibrium concentrate of N2: 0.304M
Please provide the correct answer. We typically use ICE tables with these problems but I need help
Write the expression for the equilibrium constant K, for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH, as (P NH3)?. If either the numerator or denominator is 1, please enter 1 2 Pb304(s) +→ 6 PbO(s) + O2(g) K =