The equilibrium constant, K., for the following reaction is 55.6 at 698 K. H2 (g) + I2 (g) =2 HI (g) Calculate the equilibrium concentrations of reactants and product when 0.220 moles of H2 and 0.220 moles of I, are introduced into a 1.00 L vessel at 698 [H2 ] = M [1 ] M %3D [ HI ] = M
The equilibrium constant, K., for the following reaction is 55.6 at 698 K. H2 (g) + I2 (g) =2 HI (g) Calculate the equilibrium concentrations of reactants and product when 0.220 moles of H2 and 0.220 moles of I, are introduced into a 1.00 L vessel at 698 [H2 ] = M [1 ] M %3D [ HI ] = M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![**Equilibrium Constant Calculation**
The equilibrium constant, \( K_c \), for the following reaction is **55.6 at 698 K**.
\[
\textbf{H}_2 \, (g) + \textbf{I}_2 \, (g) \rightleftharpoons 2 \, \textbf{HI} \, (g)
\]
*Calculate the equilibrium concentrations of reactants and product when 0.220 moles of \(\textbf{H}_2\) and 0.220 moles of \(\textbf{I}_2\) are introduced into a 1.00 L vessel at 698 K.*
\[ [ \text{H}_2 ] = \hspace{60pt} \text{M} \]
\[ [ \text{I}_2 ] = \hspace{60pt} \text{M} \]
\[ [ \text{HI} ] = \hspace{60pt} \text{M} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcddd9253-3f40-42a6-9522-fda4ab88f757%2F1754fb7b-7109-4f0b-8178-4c66df8f21c0%2F8pstg7_processed.png&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constant Calculation**
The equilibrium constant, \( K_c \), for the following reaction is **55.6 at 698 K**.
\[
\textbf{H}_2 \, (g) + \textbf{I}_2 \, (g) \rightleftharpoons 2 \, \textbf{HI} \, (g)
\]
*Calculate the equilibrium concentrations of reactants and product when 0.220 moles of \(\textbf{H}_2\) and 0.220 moles of \(\textbf{I}_2\) are introduced into a 1.00 L vessel at 698 K.*
\[ [ \text{H}_2 ] = \hspace{60pt} \text{M} \]
\[ [ \text{I}_2 ] = \hspace{60pt} \text{M} \]
\[ [ \text{HI} ] = \hspace{60pt} \text{M} \]
![The equilibrium constant, \( K_c \), for the following reaction is \( 1.80 \times 10^{-2} \) at \( 698 \, \text{K} \).
\[ 2\text{HI}(g) \rightleftharpoons \text{H}_2(g) + \text{I}_2(g) \]
Calculate the equilibrium concentrations of reactant and products when \( 0.362 \) moles of \(\text{HI}\) are introduced into a \( 1.00 \, \text{L} \) vessel at \( 698 \, \text{K} \).
\[
[\text{HI}] = \boxed{\hspace{2cm}} \, \text{M}
\]
\[
[\text{H}_2] = \boxed{\hspace{2cm}} \, \text{M}
\]
\[
[\text{I}_2] = \boxed{\hspace{2cm}} \, \text{M}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcddd9253-3f40-42a6-9522-fda4ab88f757%2F1754fb7b-7109-4f0b-8178-4c66df8f21c0%2Ftehvbel_processed.png&w=3840&q=75)
Transcribed Image Text:The equilibrium constant, \( K_c \), for the following reaction is \( 1.80 \times 10^{-2} \) at \( 698 \, \text{K} \).
\[ 2\text{HI}(g) \rightleftharpoons \text{H}_2(g) + \text{I}_2(g) \]
Calculate the equilibrium concentrations of reactant and products when \( 0.362 \) moles of \(\text{HI}\) are introduced into a \( 1.00 \, \text{L} \) vessel at \( 698 \, \text{K} \).
\[
[\text{HI}] = \boxed{\hspace{2cm}} \, \text{M}
\]
\[
[\text{H}_2] = \boxed{\hspace{2cm}} \, \text{M}
\]
\[
[\text{I}_2] = \boxed{\hspace{2cm}} \, \text{M}
\]
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