A mixture of ammonia, nitrogen and hydrogen was allowed to come to equilibrium at 900 K. 2NH3 3H2 + N2 Ke = 0.0076 An analysis of the mixture at equilibrium revealed 0.31 M of H2 and 1.8 M of NH3. Determine the equilibrium concentration of N2 (in M) in this mixture. (with 2 significant figures)
A mixture of ammonia, nitrogen and hydrogen was allowed to come to equilibrium at 900 K. 2NH3 3H2 + N2 Ke = 0.0076 An analysis of the mixture at equilibrium revealed 0.31 M of H2 and 1.8 M of NH3. Determine the equilibrium concentration of N2 (in M) in this mixture. (with 2 significant figures)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Equilibrium and Concentration Calculation**
A mixture of ammonia, nitrogen, and hydrogen was allowed to come to equilibrium at 900 K.
**Reaction Equation:**
\[ 2\text{NH}_3 \rightarrow 3\text{H}_2 + \text{N}_2 \]
**Equilibrium Constant:**
\[ K_c = 0.0076 \]
**Analysis of the Mixture at Equilibrium:**
- The concentration of \(\text{H}_2\) was found to be 0.31 M.
- The concentration of \(\text{NH}_3\) was found to be 1.8 M.
**Task:**
Determine the equilibrium concentration of \(\text{N}_2\) (in M) in this mixture. Express your answer with 2 significant figures.
**Solution Approach:**
To find the concentration of \(\text{N}_2\), use the equilibrium expression and the initial/known concentrations to solve for the unknowns.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18593a3a-b463-4aeb-a821-a472ffee6b36%2Fcadb1021-852d-4b4a-a0c5-9079804a776a%2F46kh8x8_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Equilibrium and Concentration Calculation**
A mixture of ammonia, nitrogen, and hydrogen was allowed to come to equilibrium at 900 K.
**Reaction Equation:**
\[ 2\text{NH}_3 \rightarrow 3\text{H}_2 + \text{N}_2 \]
**Equilibrium Constant:**
\[ K_c = 0.0076 \]
**Analysis of the Mixture at Equilibrium:**
- The concentration of \(\text{H}_2\) was found to be 0.31 M.
- The concentration of \(\text{NH}_3\) was found to be 1.8 M.
**Task:**
Determine the equilibrium concentration of \(\text{N}_2\) (in M) in this mixture. Express your answer with 2 significant figures.
**Solution Approach:**
To find the concentration of \(\text{N}_2\), use the equilibrium expression and the initial/known concentrations to solve for the unknowns.
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