A mixture of ammonia, nitrogen and hydrogen was allowed to come to equilibrium at 900 K. 2NH3 3H2 + N2 Ke = 0.0076 An analysis of the mixture at equilibrium revealed 0.31 M of H2 and 1.8 M of NH3. Determine the equilibrium concentration of N2 (in M) in this mixture. (with 2 significant figures)

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**Chemical Equilibrium and Concentration Calculation**

A mixture of ammonia, nitrogen, and hydrogen was allowed to come to equilibrium at 900 K.

**Reaction Equation:**
\[ 2\text{NH}_3 \rightarrow 3\text{H}_2 + \text{N}_2 \]
**Equilibrium Constant:**
\[ K_c = 0.0076 \]

**Analysis of the Mixture at Equilibrium:**
- The concentration of \(\text{H}_2\) was found to be 0.31 M.
- The concentration of \(\text{NH}_3\) was found to be 1.8 M.

**Task:**
Determine the equilibrium concentration of \(\text{N}_2\) (in M) in this mixture. Express your answer with 2 significant figures.

**Solution Approach:**
To find the concentration of \(\text{N}_2\), use the equilibrium expression and the initial/known concentrations to solve for the unknowns.
Transcribed Image Text:**Chemical Equilibrium and Concentration Calculation** A mixture of ammonia, nitrogen, and hydrogen was allowed to come to equilibrium at 900 K. **Reaction Equation:** \[ 2\text{NH}_3 \rightarrow 3\text{H}_2 + \text{N}_2 \] **Equilibrium Constant:** \[ K_c = 0.0076 \] **Analysis of the Mixture at Equilibrium:** - The concentration of \(\text{H}_2\) was found to be 0.31 M. - The concentration of \(\text{NH}_3\) was found to be 1.8 M. **Task:** Determine the equilibrium concentration of \(\text{N}_2\) (in M) in this mixture. Express your answer with 2 significant figures. **Solution Approach:** To find the concentration of \(\text{N}_2\), use the equilibrium expression and the initial/known concentrations to solve for the unknowns.
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