The equilibrium constant, Kp, for the following reaction is 0.250 at 613 K: NH4CI(S)NH₂(9) + HCI(g) Calculate the partial pressure of each gas and the total pressure at equilibrium when 0.229 moles of NH4CI(s) is introduced into a 1.00 L vessel at 613 K. Assume that the volume occupied by the solid is negligible. PNH₂ PHCI= Ptotal = = atm atm atm

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The equilibrium constant, Kp, for the following reaction is 0.250 at 613 K:

NH4Cl(s)  NH3(g) + HCl(g)

Calculate the partial pressure of each gas and the total pressure at equilibrium when 0.229 moles of NH4Cl(s) is introduced into a 1.00 L vessel at 613 K. Assume that the volume occupied by the solid is negligible.

PNH3 =  atm

PHCl =  atm

Ptotal =  atm

The equilibrium constant, K., for the following reaction is 0.250 at 613 K:
NH4CI(S) NH3(g) + HCI(g)
Calculate the partial pressure of each gas and the total pressure at equilibrium when 0.229 moles of NH4Cl(s) is introduced into a 1.00 L vessel at 613 K. Assume that the volume occupied by the solid is negligible.
PNHS
PHCI=
Ptotal =
=
atm
atm
atm
Transcribed Image Text:The equilibrium constant, K., for the following reaction is 0.250 at 613 K: NH4CI(S) NH3(g) + HCI(g) Calculate the partial pressure of each gas and the total pressure at equilibrium when 0.229 moles of NH4Cl(s) is introduced into a 1.00 L vessel at 613 K. Assume that the volume occupied by the solid is negligible. PNHS PHCI= Ptotal = = atm atm atm
Expert Solution
Step 1: Defining equilibrium constant

Answer:

For any chemical reaction, value of equilibrium constant KP is equal to the ratio of partial pressure of product gases and reactant gases at equilibrium.

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