#include int main() { int a, b, i = 0; a = 2047; b = 2;
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A: The solution to the given problem is below.
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A: Correct Option: A
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A: Option A is the correct answer Reason: I run the program and checked the output
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- class Main { // this function will return the number elements in the given range public static int getCountInRange(int[] array, int lower, int upper) { int count = 0; // to count the numbers // this loop will count the numbers in the range for (int i = 0; i < array.length; i++) { // if element is in the range if (array[i] >= lower && array[i] <= upper) count++; } return count; } public static void main(String[] args) { // array int array[] = {1,2,3,4,5,6,7,8,9,0}; // ower and upper range int lower = 1, upper = 9; // throwing an exception…#include<iostream>#include<math.h>using namespace std;class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in series…C++ Coding: ArraysTrue and False Code function definitions for eoNum() and output(): Both eoNum() and output() are recursive functions. output() stores the even/odd value in an array. Store 0 if the element in the data array is even and store 1 if the element in the data array is odd. eoNum() displays all the values in an array to the console.
- Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in reverse binary For an integer x, the algorithm is As long as x is greater than 0. Output x2 (remainder is either 0 or 1) *-*/2 Note: The above algorithm outputs the 0's and 1's in reverse order. Exif the input is 16 the output is 011#include <stdio.h>#include <string.h> struct user { char user_name[10]; char bank_name[10]; int account_num[4]; int card_number[14]; int pass[4]; int balance; int wallet_num[11];}; int num_acc;int withdrawal;int deposition;char transaction;int k;int number_of_papers;int choice4; void print_array(int arr[], int size){ for (int i = 0; i < size; i++) { printf("%d", arr[i]); } printf("\n");} void print_struct(char username[], char bankname[], int accountnum[], int size3, int cardnum[], int size4, int balance){ printf("Username is %s", username); printf("\nBankname is %s\n", bankname); printf("Account number is "); print_array(accountnum, size3); printf("Cardnumber is "); print_array(cardnum, size4); printf("Balance is %d\n", balance);} void scan_array(int arr[], int size){ for (int i = 0; i < size; i++) { scanf_s("%d", &arr[i]); } } int search_name_in_array(struct user user[], int size1, char…None
- int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…#include <iostream> #include<string.h> //user-defined functions question! using namespace std; struct Books { char title[50]; char author[50]; char subject[100]; int book_id; }; int main() { double array1[5]= {13.768,4.0,88.7689,9.12,}; struct Books Book1; strcpy( Book1.title, "C++ Programming"); strcpy( Book1.author, "D.S Malik"); strcpy( Book1.subject, "C++ basics"); Book1.book_id = 6495407; ////Block#1////// int x=4; for (x; x>=0; x--){ cout<<array1[x]<<endl; //////////////////////////////// } cout<<"///////////////////////"<<endl; ////end of Block#1////// ////Block#2////// int sum=0, i=0; for (i; i<5; i++){ cout<<static_cast<int>(array1[i])<<" "; sum= sum+array1[i]; cout<<sum<<endl; } cout<< "final value of sum="<<" "<<sum<<endl; cout<< "the average value ="<<" " <<sum/5 <<endl; cout<<"//////////////////////"<<endl; //Programming tracing C language Please help it is tracing on c programming kindly input the visual tracing like line where the process start or error Trace the following program: #include<stdio.h>#include<conio.h>void kar1(char *a, char *b, char *c){*a = 'c'; *b='a'; *c ='b';printf("%c %c %c\n", *a, *b, *c);}main(){char a = 'c', b = 'b', c = 'a';clrscr();printf("%c %c %c\n", a, b, c);kar1(&a,&b,&c);printf("%c %c %c\n", a, b, c);kar1(&c,&b,&a);printf("%c %c %c\n", a, b, c);kar1(&b,&a,&c);printf("%c %c %c\n", a, b, c);getch();return 0;}