Assuming that the refrigeration device can operate reversibly, using the data below, estimate theamount of heat absorbed from the cold-temperature region qC and the heat rejected to the high-temperature region qH .Hint: it may be helpful to note that the temperature changes for certain processes are small(e.g., 1 → 2 and3 → 4). In such situations, one might presume qrev ≈ ∫sfs0 Tds where T is the mean temperature of the process. In this problem, you will consider an "unusual"solid-state refrigeration device that achieves coolingby varying the magnetization of the working mate-rial (gadolinium sulphate octahydrate) at constant-pressure conditions. By contrast, most refrigerationcycles achieve cooling based on manipulating pres-sures of the working fluid. The device functionsroughly as shown at the right wherein a paramag-netic wheel is rotated through different regions:• i) a low-temperature region (1 → 2)ii) a low-magnetic field region (2 → 3)iii) a high-temperature region (3 → 4)iv) a high-magnetic field region (4 → 1)In the figure, the thermodynamic state at the point ofentry/exit from each region is shown.T₁ = 1.1 KB₁ = 0.9 TeslaLow temperature "reservoir"QcT₂ = 0.9 KB₂ = 0.0 Teslahighmagnetic fieldrotatingmagneticwheellowmagnetic fieldT₁ = 9.5 KB₁ = 6.4 TeslaQHhigh temperature "reservoir"T3 = 8.0 KB3 = 1.6 Tesla T(K)Temperature,10B= 10 TeslaB8.Nesla0.0RR = 8.314 J/(mol K)B0.5Riso-magnetic field curves6.4 TeslaB = 4,9 TeslaB 3.6 TeslaB 2.5 TeslaB=1.6 TeslaB=0.9 Tesla1.0REntropy, S1.5RB=0.4 Tesla2.0RB = 0.0 Tesla

Answered: In this problem, you will consider an…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Assuming that the refrigeration device can operate reversibly, using the data below, estimate the
amount of heat absorbed from the cold-temperature region qC and the heat rejected to the high-temperature region qH .

Hint: it may be helpful to note that the temperature changes for certain processes are small(e.g., 1 → 2 and
3 → 4). In such situations, one might presume qrev ≈ ∫^sf_s0Tds where T is the mean temperature of the process.

In this problem, you will consider an "unusual"
solid-state refrigeration device that achieves cooling
by varying the magnetization of the working mate-
rial (gadolinium sulphate octahydrate) at constant-
pressure conditions. By contrast, most refrigeration
cycles achieve cooling based on manipulating pres-
sures of the working fluid. The device functions
roughly as shown at the right wherein a paramag-
netic wheel is rotated through different regions:
• i) a low-temperature region (1 → 2)
ii) a low-magnetic field region (2 → 3)
iii) a high-temperature region (3 → 4)
iv) a high-magnetic field region (4 → 1)
In the figure, the thermodynamic state at the point of
entry/exit from each region is shown.
T₁ = 1.1 K
B₁ = 0.9 Tesla
Low temperature "reservoir"
Qc
T₂ = 0.9 K
B₂ = 0.0 Tesla
high
magnetic field
rotating
magnetic
wheel
low
magnetic field
T₁ = 9.5 K
B₁ = 6.4 Tesla
QH
high temperature "reservoir"
T3 = 8.0 K
B3 = 1.6 Tesla

T(K)
Temperature,
10
B= 10 Tesla
B8.Nesla
0.0R
R = 8.314 J/(mol K)
B
0.5R
iso-magnetic field curves
6.4 Tesla
B = 4,9 Tesla
B 3.6 Tesla
B 2.5 Tesla
B=1.6 Tesla
B=0.9 Tesla
1.0R
Entropy, S
1.5R
B=0.4 Tesla
2.0R
B = 0.0 Tesla

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