A refrigerator operates according to a Brayton cycle, diagrammed below. The gas conditions (gamma=1.4) at point 1 are P1,V1 and T1=100K. It is known that V1 =10V2=5V3=V4/2.Consider that Tf is the temperature of the cold source and Tq is the temperature of the hot source. It is known that Tq and Tf are, respectively, the maximum and minimum possible for the refrigerator to operate under these conditions. reservoirs would have a coefficient of performance closer to:
A refrigerator operates according to a Brayton cycle, diagrammed below. The gas conditions (gamma=1.4) at point 1 are P1,V1 and T1=100K. It is known that V1 =10V2=5V3=V4/2.Consider that Tf is the temperature of the cold source and Tq is the temperature of the hot source. It is known that Tq and Tf are, respectively, the maximum and minimum possible for the refrigerator to operate under these conditions. reservoirs would have a coefficient of performance closer to:
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A refrigerator operates according to a Brayton cycle, diagrammed below. The gas conditions (gamma=1.4) at point 1 are P1,V1 and T1=100K. It is known that V1 =10V2=5V3=V4/2.Consider that Tf is the temperature of the cold source and Tq is the temperature of the hot source. It is known that Tq and Tf are, respectively, the maximum and minimum possible for the refrigerator to operate under these conditions. reservoirs would have a coefficient of performance closer to:
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