In the lab where you work, a graduate student has created a K+ leak channel that is mutated in such a way that it no longer allow K+ ions to move through the channel, and instead allows only Na+ ions to move through the K+ leak channel. Assume that the equilibrium potential of Na+ is +63 mV, the equilibrium potential of K+ is -82mV, and the membrane potential is -60mV. Disregarding the actions of the Na+/K+ pump, how would ions move through the mutated K+ leak channel in a cell with normal ion concentrations? A) Na+ will leave the cell due to both the chemical and electrical gradients until the membrane potential reaches ENa+, B) Na+ will enter the cell due to both chemical and electrical gradients until the membrane potential reaches ENa+. OC) K+ will leave the cell due to both its chemical and electrical gradients until the membrane potential reaches EK+. D) K+ will leave the cell only due to its chemical gradient until it reaches OmV OE) Na+ will leave the cell due to its electrical gradient until the membrane potential reaches OmV.
In the lab where you work, a graduate student has created a K+ leak channel that is mutated in such a way that it no longer allow K+ ions to move through the channel, and instead allows only Na+ ions to move through the K+ leak channel. Assume that the equilibrium potential of Na+ is +63 mV, the equilibrium potential of K+ is -82mV, and the membrane potential is -60mV. Disregarding the actions of the Na+/K+ pump, how would ions move through the mutated K+ leak channel in a cell with normal ion concentrations? A) Na+ will leave the cell due to both the chemical and electrical gradients until the membrane potential reaches ENa+, B) Na+ will enter the cell due to both chemical and electrical gradients until the membrane potential reaches ENa+. OC) K+ will leave the cell due to both its chemical and electrical gradients until the membrane potential reaches EK+. D) K+ will leave the cell only due to its chemical gradient until it reaches OmV OE) Na+ will leave the cell due to its electrical gradient until the membrane potential reaches OmV.
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:mutated K+ leak channel in a cell with normal ion concentrations?
OA) Na+ will leave the cell due to both the chemical and electrical gradients until
the membrane potential reaches ENa+.
OB) Na+ will enter the cell due to both chemical and electrical gradients until the
membrane potential reaches ENa+.
C) K+ will leave the cell due to both its chemical and electrical gradients until
the membrane potential reaches EK+.
D) K+ will leave the cell only due to its chemical gradient until it reaches OmV
E) Nat will leave the cell due to its electrical gradient until the membrane
potential reaches OmV.
OF) K+ will enter the cell due to it's chemical and electrical gradients until the
membrane potential reaches EK+.
Transcribed Image Text:In the lab where you work, a graduate student has created a K+ leak channel that is
mutated in such a way that it no longer allow K+ ions to move through the channel,
and instead allows only Na+ ions to move through the K+ leak channel. Assume that
the equilibrium potential of Na+ is +63 mV, the equilibrium potential of K+ is -82mV,
and the membrane potential is -60mV.
Disregarding the actions of the Na+/K+ pump, how would ions move through the
mutated K+ leak channel in a cell with normal ion concentrations?
A) Na+ will leave the cell due to both the chemical and electrical gradients until
the membrane potential reaches ENa+.
B) Na+ will enter the cell due to both chemical and electrical gradients until the
membrane potential reaches ENa+.
OC) K+ will leave the cell due to both its chemical and electrical gradients until
the membrane potential reaches EK+.
D) K+ will leave the cell only due to its chemical gradient until it reaches OmV
E) Na+ will leave the cell due to its electrical gradient until the membrane
potential reaches OmV.
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