In the following scenarios, determine whether the reaction will proceed forward, reverse, or if equilibrium is reached: CaC:04) Ca ()+C₂04²(g) The ion product constant is 2.5 x 10-10. The solubility product constant is 2.3 x 10⁹ a. b. C. PbCl₂= Pb²+2C1 The ion product constant is 5.0 x 10. The solubility product constant is 1.6 x 10-³ BaSO40) Ba²+SO² The ion product constant is 2.5 x 10³. The solubility product constant is 1.1 x 10-10

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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QUESTION 7
In the following scenarios, determine whether the reaction will proceed forward, reverse, or if
equilibrium is reached:
CaC204(0) Ca (aq) +C₂O4(q)
The ion product constant is 2.5 x 10-10. The solubility product constant is 2.3 x 10"
a.
b.
C.
PbCl2 Pb² + 2Cl
The ion product constant is 5.0 x 10. The solubility product constant is 1.6 x 10-5
BaSO4) Ba²+ SO4²
The ion product constant is 2,5 x 10. The solubility product constant is 1.1 x 10-10
Transcribed Image Text:QUESTION 7 In the following scenarios, determine whether the reaction will proceed forward, reverse, or if equilibrium is reached: CaC204(0) Ca (aq) +C₂O4(q) The ion product constant is 2.5 x 10-10. The solubility product constant is 2.3 x 10" a. b. C. PbCl2 Pb² + 2Cl The ion product constant is 5.0 x 10. The solubility product constant is 1.6 x 10-5 BaSO4) Ba²+ SO4² The ion product constant is 2,5 x 10. The solubility product constant is 1.1 x 10-10
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