QUESTION 2 If the equilibrium constant for reaction X is K. What is the equilibrium constant for reaction Y is? Reaction X: SO2 (g) + (1/2) O2 (g) = SO3 (g) Reaction Y: 2 SO3 (g) = 2 SO2 (g) + O2 (g) O a.-K2 O b. 1/K2 Oc. K2 O d. 2K Oe. 0.5 xk

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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OC.NO, one is pressure past and one is concentration based. They can never have the same no
value.
OD. No, one is pressure based and one is concentration based. They could possibly have the same
numeric value.
QUESTION 2
If the equilibrium constant for reaction X is K. What is the equilibrium constant for reaction Y is?
Reaction X: SO2 (g) + (1/2) O2 (g) = SO3 (g)
Reaction Y: 2 SO3 (g) = 2 SO2 (g) + O2 (g)
O a.-K2
O b. 1/K2
Oc. K2
O d. 2K
O e. 0.5 x K
QUESTION 3
The equilibrium-constant expression depends on the
Click Save and Submit to save and submit. Click Save All Answers to save all answers.
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BARNAVE
BA
15,
O Search
16
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Transcribed Image Text:tra/courses/_153948_1/cl/outl Question Completion Status: OC.NO, one is pressure past and one is concentration based. They can never have the same no value. OD. No, one is pressure based and one is concentration based. They could possibly have the same numeric value. QUESTION 2 If the equilibrium constant for reaction X is K. What is the equilibrium constant for reaction Y is? Reaction X: SO2 (g) + (1/2) O2 (g) = SO3 (g) Reaction Y: 2 SO3 (g) = 2 SO2 (g) + O2 (g) O a.-K2 O b. 1/K2 Oc. K2 O d. 2K O e. 0.5 x K QUESTION 3 The equilibrium-constant expression depends on the Click Save and Submit to save and submit. Click Save All Answers to save all answers. O BARNAVE BA 15, O Search 16 of the reaction. hp fo f10 f11 Save All A to
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