Consider the general reaction below. 2A(g) + B₂(g) → g) ⇒ 2AB(g K = 6.4 x 10-6 @ 298 K The reaction was initiated by combining 0.70 mol A and 0.90 mol B2 in a 2.0 L container. Calculate the equilibrium concentrations of the components. What is the equilibrium concentration of AB? [AB] = [? ] × 10¹?] M

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### Chemical Equilibrium and Reaction Calculations

Consider the general reaction below:

\[ 2A(g) + B_2(g) \rightleftharpoons 2AB(g) \]

\[ K = 6.4 \times 10^{-6} \ \text{@ 298 K} \]

The reaction was initiated by combining 0.70 mol of \( A \) and 0.90 mol of \( B_2 \) in a 2.0 L container. 

**Problem: Calculate the equilibrium concentrations of the components. What is the equilibrium concentration of \( AB \)?**

\[ [AB] = \boxed{?} \times 10^{\boxed{?}} \ \text{M} \]
Transcribed Image Text:### Chemical Equilibrium and Reaction Calculations Consider the general reaction below: \[ 2A(g) + B_2(g) \rightleftharpoons 2AB(g) \] \[ K = 6.4 \times 10^{-6} \ \text{@ 298 K} \] The reaction was initiated by combining 0.70 mol of \( A \) and 0.90 mol of \( B_2 \) in a 2.0 L container. **Problem: Calculate the equilibrium concentrations of the components. What is the equilibrium concentration of \( AB \)?** \[ [AB] = \boxed{?} \times 10^{\boxed{?}} \ \text{M} \]
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