Homework Help is Here – Start Your Trial Now!
Science
Chemistry
In the following dehydration reaction three elimination products are formed. After analysis the percentage of products formed was 64%, 33% and 3%. Match the product with the percent yield. Match the following items, then click 'Submit': O Hold and drag to reorder 64% = 1. 33% = 2. 3% = 3. OH H,SO, mixture of products heat

In the following dehydration reaction three elimination products are formed. After analysis the percentage of products formed was 64%, 33% and 3%. Match the product with the percent yield. Match the following items, then click 'Submit': O Hold and drag to reorder 64% = 1. 33% = 2. 3% = 3. OH H,SO, mixture of products heat

Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter13: Substitution
Section: Chapter Questions
Problem 2E
See similar textbooks
icon
Related questions
Question
**Dehydration Reaction and Elimination Products** In the following dehydration reaction, three elimination products are formed. After analysis, the percentage of products formed was 64%, 33%, and 3%. Match the product to the percent yield. Match the following items, then click 'Submit': **Hold and drag to reorder** - 64% - 33% - 3% Below are the given products from the dehydration reaction. **Chemical Reaction:** Starting Material: - A compound with a hydroxyl group (OH) attached to a carbon that is secondary (i.e., the carbon is connected to two other carbons, and one hydrogen). Reagents and Conditions: - Sulfuric acid (H₂SO₄) and heat are used to carry out the reaction, leading to a mixture of products. **Products from the Reaction:** 1. **Product 1** - Structural Formula: The double bond is in a terminal position making a carbon-carbon double bond with a methyl group (CH₃) and other alkyl substituents. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%. 2. **Product 2** - Structural Formula: The double bond is in a more substituted position involving two internal carbons. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%. 3. **Product 3** - Structural Formula: The double bond is placed in between the internal carbons but includes fewer substituents compared to Product 2. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%. **Graphs/Diagrams Explanation:** In the given reaction diagram: - The starting compound with a hydroxyl group undergoes elimination in the presence of sulfuric acid and heat, resulting in multiple products. - Product 1 has the double bond at the terminal position. - Product 2 has a more substituted internal double bond. - Product 3 has an internal double bond but with fewer substituents. Drag and match the percent yields of 64%, 33%, and 3% to the correct products.
Transcribed Image Text:**Dehydration Reaction and Elimination Products** In the following dehydration reaction, three elimination products are formed. After analysis, the percentage of products formed was 64%, 33%, and 3%. Match the product to the percent yield. Match the following items, then click 'Submit': **Hold and drag to reorder** - 64% - 33% - 3% Below are the given products from the dehydration reaction. **Chemical Reaction:** Starting Material: - A compound with a hydroxyl group (OH) attached to a carbon that is secondary (i.e., the carbon is connected to two other carbons, and one hydrogen). Reagents and Conditions: - Sulfuric acid (H₂SO₄) and heat are used to carry out the reaction, leading to a mixture of products. **Products from the Reaction:** 1. **Product 1** - Structural Formula: The double bond is in a terminal position making a carbon-carbon double bond with a methyl group (CH₃) and other alkyl substituents. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%. 2. **Product 2** - Structural Formula: The double bond is in a more substituted position involving two internal carbons. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%. 3. **Product 3** - Structural Formula: The double bond is placed in between the internal carbons but includes fewer substituents compared to Product 2. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%. **Graphs/Diagrams Explanation:** In the given reaction diagram: - The starting compound with a hydroxyl group undergoes elimination in the presence of sulfuric acid and heat, resulting in multiple products. - Product 1 has the double bond at the terminal position. - Product 2 has a more substituted internal double bond. - Product 3 has an internal double bond but with fewer substituents. Drag and match the percent yields of 64%, 33%, and 3% to the correct products.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Combustion Analysis
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:
9780618974122
Author:
Andrei Straumanis
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS