**Dehydration Reaction and Elimination Products**In the following dehydration reaction, three elimination products are formed. After analysis, the percentage of products formed was 64%, 33%, and 3%. Match the product to the percent yield. Match the following items, then click 'Submit':**Hold and drag to reorder**- 64%- 33%- 3%Below are the given products from the dehydration reaction. **Chemical Reaction:**Starting Material:- A compound with a hydroxyl group (OH) attached to a carbon that is secondary (i.e., the carbon is connected to two other carbons, and one hydrogen).Reagents and Conditions:- Sulfuric acid (H₂SO₄) and heat are used to carry out the reaction, leading to a mixture of products.**Products from the Reaction:**1. **Product 1** - Structural Formula: The double bond is in a terminal position making a carbon-carbon double bond with a methyl group (CH₃) and other alkyl substituents. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%.2. **Product 2** - Structural Formula: The double bond is in a more substituted position involving two internal carbons. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%.3. **Product 3** - Structural Formula: The double bond is placed in between the internal carbons but includes fewer substituents compared to Product 2. - Yield percentage: You need to match this product to one of 64%, 33%, or 3%.**Graphs/Diagrams Explanation:**In the given reaction diagram:- The starting compound with a hydroxyl group undergoes elimination in the presence of sulfuric acid and heat, resulting in multiple products.- Product 1 has the double bond at the terminal position.- Product 2 has a more substituted internal double bond.- Product 3 has an internal double bond but with fewer substituents.Drag and match the percent yields of 64%, 33%, and 3% to the correct products.

The question is based on the concept of organic reactions. we have to identify the correct…

In the following dehydration reaction three elimination products are formed. After analysis the percentage of products formed was 64%, 33% and 3%. Match the product with the percent yield. Match the following items, then click 'Submit': O Hold and drag to reorder 64% = 1. 33% = 2. 3% = 3. OH H,SO, mixture of products heat

In the following dehydration reaction three elimination products are formed. After analysis the percentage of products formed was 64%, 33% and 3%. Match the product with the percent yield. Match the following items, then click 'Submit': O Hold and drag to reorder 64% = 1. 33% = 2. 3% = 3. OH H,SO, mixture of products heat

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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