In the figure shown, the magnitude of the uniform electric field is E = 70 kN/C . Calculate the electric flux through: %D 32.0 cm A. The vertical rectangular surface B. The slanted surface 70° C. The entire surface of the box 45.0 cm

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hyp- 0.4789 m
-EA cos 180°
O: (70 kN/C) (0.32 m x 0.1638 m) (-1)
4: - 3.6688 KNmc
O: EA cos 70°
= (10KN/C) (0.4789 m x 0.32 m) (0.3420)
KN m
0= 3. 6688 /c
total -3.6688 KNm/c + 3.668s N mc
Ototal
o kN m/c
Transcribed Image Text:hyp- 0.4789 m -EA cos 180° O: (70 kN/C) (0.32 m x 0.1638 m) (-1) 4: - 3.6688 KNmc O: EA cos 70° = (10KN/C) (0.4789 m x 0.32 m) (0.3420) KN m 0= 3. 6688 /c total -3.6688 KNm/c + 3.668s N mc Ototal o kN m/c
In the figure shown, the magnitude of the uniform electric
field is E = 70 kN/C . Calculate the electric flux through:
32.0 cm
A. The vertical rectangular surface
B. The slanted surface
70°
C. The entire surface of the box
45.0 cm*
Transcribed Image Text:In the figure shown, the magnitude of the uniform electric field is E = 70 kN/C . Calculate the electric flux through: 32.0 cm A. The vertical rectangular surface B. The slanted surface 70° C. The entire surface of the box 45.0 cm*
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