In the current mirror shown controlled by the current source lIN, for identical transistors, then the output current loUt is: Vcc IOUT = Ica IN Vor VIN а. lout = lIN / [1+ 2/(B(1+B)] b. louT = lIN / [B/(B(1+B)] %3D
In the current mirror shown controlled by the current source lIN, for identical transistors, then the output current loUt is: Vcc IOUT = Ica IN Vor VIN а. lout = lIN / [1+ 2/(B(1+B)] b. louT = lIN / [B/(B(1+B)] %3D
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Ever since electricity has been created, people have started using it in its entirety. We see many types of Transformers in the neighborhoods. Some are smaller in size and some are very large. They are used according to their requirements. Many of us have seen the electrical transformer but they do not know what work they are engaged in.
Question
Q2
![In the current mirror shown
controlled by the current source
IIN, for identical transistors, then
the output current loUT is:
Vcc
IOUT = Ic39
IN
Q2
VouT
VIN
lout = lIN / [1+ 2/(B(1+B)]
b.
lout = lIN / [B/(B(1+B)]
С.
louT = lIN / [1+ 1/(B(1+B)]
d.
loUT = lIN / [2+ 1/(B(1+B)]
a.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e9364ac-6842-43b0-9022-ccb293971af7%2F58254326-be5e-456e-ba6a-5053afa9bf48%2Fka8bdgn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In the current mirror shown
controlled by the current source
IIN, for identical transistors, then
the output current loUT is:
Vcc
IOUT = Ic39
IN
Q2
VouT
VIN
lout = lIN / [1+ 2/(B(1+B)]
b.
lout = lIN / [B/(B(1+B)]
С.
louT = lIN / [1+ 1/(B(1+B)]
d.
loUT = lIN / [2+ 1/(B(1+B)]
a.
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