Draw, Illustrate and label your schematic diagram before solving the problem

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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 Draw, Illustrate and label your schematic diagram before solving the problem.

1.) Given a Fixed-Biased transistor circuit with Beta DC is 200 , voltage at common collector is +22v ,base supply voltage is +11V, Base resistor is 47kOhms , collector resistor is 390 ohms ,Voltage at Base-emitter junction  is 0.7v. Determine the Q-point of collector current and Voltage at collector-emitter junction. 

These is the example or guide that might help in answering the problem.

 

Examples:
1. Fixed Bias
Determine the collector current Ic, base Step
current IB and collector-to-emitter IB.
voltage VCE, given that the base-to-
emitter voltage VBe is 0.7v.
Step 2: Solve for the collector
current Ic.
Solve for the base current
Vcc – VBe
IR =
RB
12v – 0.7v
IR =
Ic = Bpc!B
Ic = 50(47.08 µA)
Ic = 2.35mA
240kN
IR = 47.08 µA
+12v
Step 3: Solve for the collector-to-
emitter voltage Vce -
240kN
2.2kN
VCE = Vcc - IcRC
VCe = 12v – 2.35mA(2.2kN)
VCE = 6.83v
VIN
B = 50
GND
Transcribed Image Text:Examples: 1. Fixed Bias Determine the collector current Ic, base Step current IB and collector-to-emitter IB. voltage VCE, given that the base-to- emitter voltage VBe is 0.7v. Step 2: Solve for the collector current Ic. Solve for the base current Vcc – VBe IR = RB 12v – 0.7v IR = Ic = Bpc!B Ic = 50(47.08 µA) Ic = 2.35mA 240kN IR = 47.08 µA +12v Step 3: Solve for the collector-to- emitter voltage Vce - 240kN 2.2kN VCE = Vcc - IcRC VCe = 12v – 2.35mA(2.2kN) VCE = 6.83v VIN B = 50 GND
Biasing BJT Circuits
Transistor biasing largely depends on transistor beta (B).
Fixed Bias
Vcc – VBE
IR =
Vcc
오
The circuit shown is called a "fixed base
RB
Ic = Boc'B
VCE = Vcc - IcRc
Vce = Vc – VE
VBE = VB – VE
.. VE = Ov
VCE = Vc
Vbe = VB
bias circuit" because the transistors
base current, IR remains constant for
Rp
Rc
given values of Vcc, and therefore the
transistors operating point must also
remain fixed. This two-resistor biasing
Bpc
VIN O-
VR
VCE
network is used to establish the initial
VRE
operating region of the transistor using
a fixed current bias.
GND
Transcribed Image Text:Biasing BJT Circuits Transistor biasing largely depends on transistor beta (B). Fixed Bias Vcc – VBE IR = Vcc 오 The circuit shown is called a "fixed base RB Ic = Boc'B VCE = Vcc - IcRc Vce = Vc – VE VBE = VB – VE .. VE = Ov VCE = Vc Vbe = VB bias circuit" because the transistors base current, IR remains constant for Rp Rc given values of Vcc, and therefore the transistors operating point must also remain fixed. This two-resistor biasing Bpc VIN O- VR VCE network is used to establish the initial VRE operating region of the transistor using a fixed current bias. GND
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