Problem 05.017 - Inverting amplifier with adjustable voltage gainIn the circuit given below, R₁ = 15 kN, R₂ = 66 kſ, and R3 = 4 MS. Calculate the gain when the switch is in position 1, position 2, andposition 3.ViThe gainThe gainThe gain5 ΚΩVoViR₁wwwR₂R3at the position 1 isat the position 2 isat the position 3 is3110 kQ2VOViV

Answered: Image /qna-images/answer/9c049692-c888-4251-bee6-ffe67961e1ed.jpg

Answered: In the circuit given below, R₁ = 15 k,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Using 2nd approximation
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In the circuit given in the figure | VBE | = 0.7V, R1 = 11.06Kohm, R2 = 48.24Kohm, RC = 1.03Kohm, RE = 3.09Kohm, VCC = -13.00V, Beta = 150.00, calculate the IC current by full analysis.
Q.1 For the amplifier in figure befow, deternrine the following: 1- Ad ino A- 'A- 10 mV rms 560 kN RB 1.5 k2
A silicon photodiode is connected to an op-amp as indicated. Under an illuminance of 500 lux, the photocurrent Ip is 80 nA. I R = 1MQ w out Write down the values of 11, 12 and Ip. From these values, deduce the output voltage. Briefly describe how this circuit works. c) Will this circuit work under sunlight? The illuminance of sunlight is about 100,000 lux. You may assume the photocurrent respond linearly with incident light flux, and the op-amp is powered between 9V alkaline cell. (i.e., V+ = 9V, V¯ at ground).
Determine the output signal for the op-amp circuit shown in figure below, given Rf1 = 10 km, Rf2 = 5 ΚΩ, R = 1 ΚΩ. . R₁12 R41 #.. www V01 V₁-W V₂ w R Vov 02
4. A current measuring operational amplifier is made by bridging a resistor across the inverting terminal (pin 2) and the output terminal (pin 6). The noninverting terminal is grounded. a. Draw a sketch of the current measuring circuit. Determine an appropriate resistor for converting a current of 1.0 picoamperes (1.0 × 10-¹2 A) to a voltage of 0.010 V. (The math for this question is very easy, don't overthink this question. b. There are a few reasons that circuit you drew in part a will not be effective. First, you will have a difficult time finding a resistance with the required resistance value. Second, the input terminals do not have infinite resistance value. In fact, for an inexpensive 741 op-amp, the input terminal resistance may only be a few MOhms, which is far less than the resistance your calculated for the feedback resistor. This means that more current will be drawn into the op-amp than will go around it. Finally, the op-amp may have a bias current that is larger than the…
Figure 1 shows the equivalent circuit of a voltage amplifier with a source and aload connected to its input and output, respectively. Suppose that the sourceinternal resistance is Rs = 5 kΩ, the amplifier input resistance is RIN = 95 kΩ, theamplifier gain is A = 100, the amplifier output resistance is ROUT = 150 Ω and theload resistance is RL = 5 kΩ. For a sinusoidal input with amplitude VS = 5 mV, whatis the amplitude of the voltage VL across the load resistor RL? What would thevoltage across the load be without the amplifier?
Please help me with my laboratory activity. Thanks a lot!
The input signal Vin shown in the figure is a 1 KHz square wave voltage that alternates between +7V and -7V with a 50% duty cycle. Both transistors have the same current gain, which is large. The circuit delivers power to the load resistor RL. What is the efficiently of this circuit for the given input? Choose the closest answer. -10V Vino O -10V MM | R₁ = 1052
DC to AC 1) Determine the efficiency of the following DC to AC converter (i.e. how much of the energy is in the Ist harmonic?). (on for 10ms (+20V), off for 20ms, on for 10ms (-20V), off for 20ms, repeat) +20V 20ms 20ms 10ms ov 10ms -20V 1) Determine the efficiency of the following DC to AC converter (i.e. how much of the energy is in the Ist harmonic?). +2-V -20V 10ms 20ms Oms 30ms 40ms

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