In recent years, approximately 55% of eligible voters take the time to vote in presidential elections. A poll based on a random sample of 200 eligible voters finds that 128 plan to vote in the next presidential election.    Does this data provide convincing evidence at the ?α = 0.05 level that the proportion of eligible voters who will take time to vote in the next presidential election differs from 0.55?

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A: given data IN THEIR 20S : n1 = 250x1  = 180IN THEIR 40S: n2  = 260x2 = 156α = 0.05claim : p1 ≠ p2

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A: From the given information we find the solution.

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A:

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A: Note: Hey there! Thank you for the question. As you have posted multiple questions, we have helped…

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A:

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A: It is given that margin of error (E) is 0.02 and the confidence level is 0.96.

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A: we have to find test  statistics..

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A: The test statistic for the difference of proportion is, Z=p1-q1P^(1-P^)1n1+1n2wherep1 and p2=sample…

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A: A random sample of  800 households was taken and 568 said that they own the pet.

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A: Given: Margin of Error ME= 0.06 Confidence level c= 0.90

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Q: The National Academy of Science reported that 41% of research in mathematics is published by US…

A: Given,n=186x=92p^=xnp^=92186=0.4946α=0.05