In quantum statistical mechanics, consider a system of independent, distinguishable particles, each of which has only two accessible states; a ground state of energy 0 and an excited state of energy ε. If the system is in equilibrium with a heat bath of temperature T, calculate A (Helmholtz free energy), E (internal energy), S (entropy), and Cv (specific heat capacity at constant volume). Does the choice of the ground-state energy equal 0 affect P (pressure), Cv, or S? How would your results change if ε0 were added to both energy values?
In quantum statistical mechanics, consider a system of independent, distinguishable particles, each of which has only two accessible states; a ground state of energy 0 and an excited state of energy ε. If the system is in equilibrium with a heat bath of temperature T, calculate A (Helmholtz free energy), E (internal energy), S (entropy), and Cv (specific heat capacity at constant volume). Does the choice of the ground-state energy equal 0 affect P (pressure), Cv, or S? How would your results change if ε0 were added to both energy values?
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