The Joule-Kelvin coefficient is given by *=().-EE).-リ (1) Since it involves the absolute temperature T, this relation can be used to deter- mine the absolute temperature T. Consider any readily measurable arbitrary temperature parameter ở (e.g., the height of a mercury column). All that is known is that ở is some (unknown) function of T; i.e., v = 8(T). (a) Express (1) in terms of the various directly measurable quantities involving the temperature parameter ở instead of the absolute temperature T, i.e., in terms of u'= (a8/ap)n, C,' = (đQ/d0)p, a' = V-(av/08), and the derivative do/&T. (6) Show that, by integrating the resulting expression, one can find T for any given value of if one knows that ở = d, when T = T. (e.g., if one knows the value of v = 8o at the triple point where To = 273.16).
The Joule-Kelvin coefficient is given by *=().-EE).-リ (1) Since it involves the absolute temperature T, this relation can be used to deter- mine the absolute temperature T. Consider any readily measurable arbitrary temperature parameter ở (e.g., the height of a mercury column). All that is known is that ở is some (unknown) function of T; i.e., v = 8(T). (a) Express (1) in terms of the various directly measurable quantities involving the temperature parameter ở instead of the absolute temperature T, i.e., in terms of u'= (a8/ap)n, C,' = (đQ/d0)p, a' = V-(av/08), and the derivative do/&T. (6) Show that, by integrating the resulting expression, one can find T for any given value of if one knows that ở = d, when T = T. (e.g., if one knows the value of v = 8o at the triple point where To = 273.16).
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Transcribed Image Text:The Joule-Kelvin coefficient ia given by
e,
V [T
(1)
Since it involves the absolute temperature T, this relation can be used to deter-
mine the absolute temperature T.
Consider any readily measurable arbitrary temperature parameter & (e.g.,
the height of a mercury column). All that is known is that & is some (unknown)
function of T; i.e., ở
(a) Express (1) in terms of the various directly measurable quantities
involving the temperature parameter & instead of the absolute temperature T,
i.e., in terms of u' = (08/0p)r, C,' = (đQ/d0), a' =
derivative do/dT.
(b) Show that, by integrating the resulting expression, one can find T for any
given value of d if one knows that &
value of o = do at the triple point where T, = 273.16).
= 8 (T).
V-(0V/80), and the
do when T = T. (e.g., if one knowa the
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