In Java only please. The following progam uses a series to find the approximate value of pi. However, the statements are in the wrong order and there is also a bug in this program. Rearrange the statements and also fine and remove the bug so that this program can be used to approximate pi   import java.util.*; public class Ch5_PrExercise2 { static Scanner console = new Scanner(System.in); public static void main(String[] args) { double pi = 0; long i ; long n;   n = console.nextOnt(); System.out.print("Enter the value of n:  "); System.out.println(); if(i % 2 == 0) pi = pi + (1 / (2 * i + 1)); else pi = pi - (1 / (2 * i + 1)); for(i = 0; i < n; i++) { pi = 0; pi = 4 * pi; } System.out.println("pi = " + [i); ) Note I know  that the code go in the following order but not sure about the order of the if-else statement.   n =System.out.print("Enter the value of n:  "); console.nextInt(); System.out.println(); for(i = 0; i < n; i++) { pi = 0; pi = 4 * pi;   for(i = 0; i < n; i++) { pi = 0; pi = 4 * pi; if(i % 2 == 0) pi = pi + (1 / (2 * i + 1)); System.out.println("pi = " + [i); else pi = pi - (1 / (2 * i + 1)); System.out.println("pi = " + [i); )

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In Java only please.

The following progam uses a series to find the approximate value of pi. However, the statements are in the wrong order and there is also a bug in this program. Rearrange the statements and also fine and remove the bug so that this program can be used to approximate pi

 

import java.util.*;

public class Ch5_PrExercise2

{

static Scanner console = new Scanner(System.in);

public static void main(String[] args)

{

double pi = 0;

long i ;

long n;

 

n = console.nextOnt();

System.out.print("Enter the value of n:  ");

System.out.println();

if(i % 2 == 0)

pi = pi + (1 / (2 * i + 1));

else

pi = pi - (1 / (2 * i + 1));

for(i = 0; i < n; i++)

{

pi = 0;

pi = 4 * pi;

}

System.out.println("pi = " + [i);

)

Note I know  that the code go in the following order but not sure about the order of the if-else statement.

 

n =System.out.print("Enter the value of n:  ");

console.nextInt();

System.out.println();

for(i = 0; i < n; i++)

{

pi = 0;

pi = 4 * pi;

 

for(i = 0; i < n; i++)

{

pi = 0;

pi = 4 * pi;

if(i % 2 == 0)

pi = pi + (1 / (2 * i + 1));

System.out.println("pi = " + [i);

else

pi = pi - (1 / (2 * i + 1));

System.out.println("pi = " + [i);

)

 

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