1 import java.util.Scanner;T23456-789101112131415161718192021222341427892526Ypublic class preLabC {public static Integer myMethod(String repeat ThisValue) {System.out.println("The computer wants you to enter the following binary number: + repeat ThisValue);// Step 1. Add in a line here to accept a new Scanner object.You're done this before... var//3031323334 }}something something... Scanner(System.in);// what goes here?// Step 2. Tell Java that the thing you're going to scan in will be in Binary form (only 1's and 0's)ObjectName DOT useRadix( SOME_NUMBER);////what number should you use in the parentheses? 2 for Binary.// the scanned object should be in binary (Radix 2)// Step 3. Scan the values from the user. It's going to return an Integer, not a String.//Integer binary Integer scannedObject.nextInt(); // capture the user entry as an Integer Object.System.out.println("In this black VPL box, enter a binary number: ");System.out.println("You entered " + binaryInteger +which in binary isreturn binary Integer;"+ Integer.toBinaryString(binaryInteger) );A String showing a Binary number will be passed to yourmethod.You should have the user (you, in this case) type out a Binarynumber within the VPL window like this...Description→ Submission✪A8910preLabC.java1- import java.util.Scanner;234- public class preLabC (56-719Submissions list<> EditSimilaritySubmission view?method.A Test activityGradepublic static Integer myMethod(String repeat ThisValue){> Console: connected (Running: 9 seg)JUnit version 4.11.Testcomputer wants you to enter the following binary number: 11Previous s11System.out.println("The computer wants you to enter the followingnew Scanner(System.in);cennedObject useRodix // the scanned object should be in binary (Radix 2)Integer binaryInteger scannedobject.nextInt(); // capture the user entry as an integer.Type your binarynumber here.Then hit enter or return.System.out.println("In this black VPL box, enter a binary number: ");System.out.println("You entered" + binaryInteger", which in binary is + Integer.toBinaryString(binary Integer));You'll have to use the Scanner class to get input from theuser. Scanner allows you to specify if the entry should betreated as a String or as an Integer, etc.When the user is expected to enter an Integer (as is the casehere), use the nextInt() method. For example:scanner.nextInt(). This is different than the nextLine()There's a wrinkle in this problem. You are to assume that theinteger that is being entered is in Binary form. That meansthat if the user enters 10 they don't mean "ten". They mean"two". To do this, you have to modify the scanner object touse a different "radix". This is also known as a base. Aregular number has a radix of 10. We often call these'decimal" numbers or "base 10" numbers because we count ingroups of ten. A binary number has a radix of 2 because youcount in groups of two: 0 then 1.How do you do this? Use the radix() method.What does a binary number look like? 0 is 0. 1 is 1. Thenumber 2? It's 10. And three? It's 11. Seven is 111. Eightis 1000.

The JAVA code is given below with output screenshot

You'll have to use the Scanner class to get input from the user. Scanner allows you to specify if the entry should be treated as a String or as an Integer, etc. When the user is expected to enter an Integer (as is the case here), use the nextInt() method. For example: scanner.nextInt(). This is different than the nextLine() method. There's a wrinkle in this problem. You are to assume that the integer that is being entered is in Binary form. That means that if the user enters 10 they don't mean "ten". They mean "two". To do this, you have to modify the scanner object to use a different "radix". This is also known as a base. A regular number has a radix of 10. We often call these 'decimal numbers or "base 10" numbers because we count in groups of ten. A binary number has a radix of 2 because you count in groups of two: 0 then 1. How do you do this? Use the radix() method. What does a binary number look like? 0 is 0. 1 is 1. The number 2? It's 10. And three? It's 11. Seven is 111. Eight 1000

You'll have to use the Scanner class to get input from the user. Scanner allows you to specify if the entry should be treated as a String or as an Integer, etc. When the user is expected to enter an Integer (as is the case here), use the nextInt() method. For example: scanner.nextInt(). This is different than the nextLine() method. There's a wrinkle in this problem. You are to assume that the integer that is being entered is in Binary form. That means that if the user enters 10 they don't mean "ten". They mean "two". To do this, you have to modify the scanner object to use a different "radix". This is also known as a base. A regular number has a radix of 10. We often call these 'decimal numbers or "base 10" numbers because we count in groups of ten. A binary number has a radix of 2 because you count in groups of two: 0 then 1. How do you do this? Use the radix() method. What does a binary number look like? 0 is 0. 1 is 1. The number 2? It's 10. And three? It's 11. Seven is 111. Eight 1000

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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