In experiment (8) "Dissociation constant of a weak acid by conductimetric method", the following data was obtained: Cell constant 1.020 cm!, conductance of electrolyte = 5.06 x 10 40, conductance of H20 = 15.5 x 10-6 Q, Given that (x (L/A) x G'), calculate x in Q cm %3! Select one: O A. 1.58 x 105 O B. 5.003 x 10-4 O C. 5.16 x 104 O D. 1.999 x 10

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In experiment (8) "Dissociation constant of a weak acid by conductimetric method", the
following data was obtained: Cell constant = 1.020 cm!, conductance of electrolyte = 5.06 x 10-
40, conductance of H-0 = 15.5 × 10-6 Q'!,
%3D
%3D
!3!
Given that (x = (L/A) x G'), calculate x in Q cm
%3D
Select one:
O A. 1.58 x 10-5
O B. 5.003 x 10-4
O C. 5.16 x 10-4
O D. 1.999 x 103
Transcribed Image Text:In experiment (8) "Dissociation constant of a weak acid by conductimetric method", the following data was obtained: Cell constant = 1.020 cm!, conductance of electrolyte = 5.06 x 10- 40, conductance of H-0 = 15.5 × 10-6 Q'!, %3D %3D !3! Given that (x = (L/A) x G'), calculate x in Q cm %3D Select one: O A. 1.58 x 10-5 O B. 5.003 x 10-4 O C. 5.16 x 10-4 O D. 1.999 x 103
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