Make a 1:100 solution of Na2SO4.10H20 in 100 ml of water from your previous solution. What is the final concentration of the Sodium lon?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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3A. Determine the Molarity of the Sodium ion
in a solution of Na2SO4.10H20 if you add
3.041 grams to a final volume of 150 ml.
Add 3.041 g of Na2SO4.10H20 in a beaker
pour upto 150ml of water to achieve 0.063
Molar.
Calculation
Na2SO4.10H20 MW = 322.03g/mol
Grams = 3.041 g
Vf = 150ml = 0.15L
M= mols of solute/ L of solution
(3.041g/1) (1mol/ 332.2g) = 0.00915mol
Na2SO4.10H20
0.00915mol N22SO4.10H20/ .15l= 0.061 M
2 Na = 2*0.061mol/L = 0.126 mol/L
Answer the question below
Make a 1:100 solution of Na2SO4.10H20 in
100 ml of water from your previous solution.
What is the final concentration of the Sodium
lon?
Transcribed Image Text:3A. Determine the Molarity of the Sodium ion in a solution of Na2SO4.10H20 if you add 3.041 grams to a final volume of 150 ml. Add 3.041 g of Na2SO4.10H20 in a beaker pour upto 150ml of water to achieve 0.063 Molar. Calculation Na2SO4.10H20 MW = 322.03g/mol Grams = 3.041 g Vf = 150ml = 0.15L M= mols of solute/ L of solution (3.041g/1) (1mol/ 332.2g) = 0.00915mol Na2SO4.10H20 0.00915mol N22SO4.10H20/ .15l= 0.061 M 2 Na = 2*0.061mol/L = 0.126 mol/L Answer the question below Make a 1:100 solution of Na2SO4.10H20 in 100 ml of water from your previous solution. What is the final concentration of the Sodium lon?
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