In building a highway, the district engineer is faced with the alternatives of building a four-lane underpass that would take care of all future needs of building a two-lane underpass now and a second two-lane underpass 20 years later. The four-lane underpass would cost 400,000 and has a maintenance cost of 10,000 per year during the 40 years it is expected an underpass will be needed. The two-lane underpass will cost 270,000 each and each would have a maintenance cost of 8,000 per year. if financing costs are 5%, which alternative should be adopted and compute the difference of its equivalent present worth. assume zero salvage value for each alternative at the end of 40 years. Use present worth method.
In building a highway, the district engineer is faced with the alternatives of building a four-lane underpass that would take care of all future needs of building a two-lane underpass now and a second two-lane underpass 20 years later. The four-lane underpass would cost 400,000 and has a maintenance cost of 10,000 per year during the 40 years it is expected an underpass will be needed. The two-lane underpass will cost 270,000 each and each would have a maintenance cost of 8,000 per year. if financing costs are 5%, which alternative should be adopted and compute the difference of its equivalent present worth. assume zero salvage value for each alternative at the end of 40 years. Use present worth method.
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