In an initial drugs test, 5.8% of job applicants tested negative. It is claimed that now the rate is lower. A random sample of 1520 current job applicants ended in 58 negative results. 1. Construct a 95% confidence interval for p, the true proportion of negative results in the population (classical form). 2. Conduct a statistical test of hypothesis on this claim at the 0.01 level of significance, by the following 5 steps. Step 1. Hypotheses and significance level: Ho: Ha: a = Step 2. Test Statistic and its sampling distribution under Ho: Step 3. Observed value of the test statistic: Step 4. P-value under Ho: Step 5. Decision and conclusion (interpretation of the result):

In an initial drugs test, 5.8% of job applicants tested negative. It is claimed that now the rate is lower. A random sample of 1520 current job applicants ended in 58 negative results. 1. Construct a 95% confidence interval for p, the true proportion of negative results in the population (classical form). 2. Conduct a statistical test of hypothesis on this claim at the 0.01 level of significance, by the following 5 steps. Step 1. Hypotheses and significance level: Ho: Ha: a = Step 2. Test Statistic and its sampling distribution under Ho: Step 3. Observed value of the test statistic: Step 4. P-value under Ho: Step 5. Decision and conclusion (interpretation of the result):

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which of the following is not true when using the confidence interval method for testing a claim about u when a is unknown? Choose the correct answer below. OA. The P-value method, the traditional method, and the confidence interval method are equivalent and yield the same results. OB. For a one-tailed hypothesis test with a 0.05 significance level, one must construct a 90% confidence interval. OC. The P-value method and the classical method are not equivalent to the confidence interval method in that they may yield different results. OD. For a two-tailed hypothesis test with a 0.05 significance level, one must construct a 95% confidence interval.
Given X = 120, u = 100, o = 15, n = 450, and 95% confidence level for two - tailed test, test the hypotheses. Step1. State the null and alternative hypotheses. Step 2. Give the significance level. Step 3. Give the critical value of z. Step 4. Compute the test statistic. Step 5. State the decision rule. Step 6. Interpret the result of the test of significance.
Fewer young people are driving. In 1983, 87% of 19-year-olds had a driver's license. Twenty-five years later that percentage had dropped to 75% (University of Michigan Transportation Research Institute website, April 7, 2012). Suppose these results are based on a random sample of 1200 19-year-olds in 1983and again in 2008. a. At 95% confidence, what is the margin of error and the internal estimate of the number of 19-year old drivers in 19SS? b. At 95 6 confidence, what is the margin of error and the interval estimate of the number of 19-year old drivers in 2008? c.Is the margin of error the same in parts (a) and (b)? Why or why not?
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We would like to compute a 98% confidence interval on the proportion of CBC students that will be transferring to a 4 year college or university after their time at CBC. The current proportion is unknown and we would like an error of no more than 1.5% in the estimate. How large of a sample needs to be taken?
Calculate the SEMean Construct a 98% confidence interval for the population scores of Mrs. Paul’s students. State the null and alternate hypothesis for this test.
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A population proportion is to be estimated from a sample of 3,600 with a sample proportion of 0.42. Approximate the margin of error for the 95% confidence interval. Round to four decimal places, if necessary. O A. 0.0003 OB. 0.0115 OC. 0.0161 O D. 0.0082 ہے
Based on data from a survey of 1,300 randomly selected Facebook users, a 95% confidence interval for the proportion of all Facebook users who say it is not OK to "friend" someone who reports to you at work is (0.60, 0.64). What is the meaning of the 95% confidence level associated with this interval? If a large number of random samples of size 1,300 were to be taken, % of the resulting confidence intervals would contain the true proportion of all Facebook users who would say it is to "friend" someone who reports to you at work.
2- You are interested in the effectiveness of a new blood pressure drug. You manage to collect a sample of 7 people's blood pressure before and after using the drug. The drug is effective if it lowers the average blood pressure by more than 2 points. Before 16 14 18 15 14 16 17 After 12 12 15 14 11 11 13 a. Construct and interpret a 95% confidence interval for the differences in population means. b. Test for the effectiveness of the drug at a=0.05.
2- You are interested in the effectiveness of a new blood pressure drug. You manage to collect a sample of 7 people's blood pressure before and after using the drug. The drug is effective if it lowers the average blood pressure by more than 2 points." Before 16 14 18 15 14 16 17e After 12 12 15 14 11 11 13 a. Construct and interpret a 95% confidence interval for the differences in population means.e b. Test for the effectiveness of the drug at a=0.05.4
Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a sample proportion of p̂=0.23. What is the margin of error?