2.A drug company claims that if you take their new wonder drug "Ainstats", that more than83% of students will see an improvment their statistics grades. Taking a survey of 352 students taking"Ainstats" we noticed that 299 improved their grades. Test the companies claim at the 0.05 confidence level.Step 1: State the hypotheses.Step 2: Calculate the test statistic.Step 3: Calculate the p-value.0I

Proportion of students with improved statistics grade as claimed by the company = 0.83 (83%) Tota…

Answered: 2. A drug company claims that if you…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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9. A researcher wants to construct a 99% confidence interval for the proportion of Americans who think that the U.S. invading Iraq was an effective step in combating world terrorism. She has no initial idea of what that proportion is. How large should her sample size be if she wants the margin of error to be at most two percent? Show or explain your thinking.
Construct a 90% confidence interval for the true proportion of all employees of People Plus Pty who believe that they should be given a raise by the company, given that 120 out of a sample of 135 employees support this suggestion. Interpret your answer.
19.
Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a sample proportion of p̂=0.23. What is the margin of error?
You sample 33 people to see if they own a dog, and find that 46% of them (rounded) do own a dog. What is the LOW end of the 95% confidence interval for this study? Leave your answer in decimal format to three decimal places. In other words, .036 instead of 3.6% or .114 instead of 11.4%..
A football coach claims that the average weight of all opposing teams’ members is 225 pounds. For a test of the claim, a simple random sample of 50 players is taken from all the opposing teams. The mean is found to be 230 pounds with a standard of 15 pounds. Construct a 95% confidence interval for the unknown average weight of the population of all the players of opposing teams. Interpret your result.
1- You want to construct a 99% confidence interval for the proportion of retail stores that went out of business due to the recent pandemic. You managed to collect a random sample of 93 retail stores and found 15% of them shut down permanently. Construct and interpret the confidence interval.
We have conducted a one sided hypothesis test with a significance level a = 0.05. We would like to also construct a confidence interval with an equivalent level so that we can compare our results. What should the confidence level of this interval be? (Note: Do not include the percent sign.)
Many people think that a national lobby's successful fight against gun control.legislation is reflecting the will of a minority of Americans. A random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. Estimate the true proportion of all Americans who are in favor of gun control legislation using a 90% confidence interval. Follow the PANIC acronym
The president’s policy on domestic affairs received a 45% approval rating in a recent poll. The margin of error was given as 0.035. What sample size was used for this poll if we assume a 95% confidence level?
ESPN believed that 30 percent of Sportszone visitors were females. To test this hypothesis, it collected audience profile data at the ESPN SportsZone Web site and found that 36% of the visitors were females. Assume that this sample value was based on a sample of 300 users. Test its hypothesis using 95% confidence level.
In a recent survey of 1264 US adults, 26.6% said they had seen a ghost. What is the LOWER endpoint of a 98% confidence interval for the population proportion? What is the UPPER endpoint of a 98% confidence interval for the population proportion? Answers should be decimals (not percentages).

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